0.25-kg block oscillates on the end of a spring with a spring constant of 200 N/m. If the oscillations is started by elongating
the spring 0.15 m and giving the block a speed of 3.0 m/s, then the maximum speed of the block is A :
1 answer:
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The period of a pendulum is given by
where L is the pendulum length and g is the gravitational acceleration.
We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
where the labels m and e refer to "Moon" and "Earth".
Since the gravitational acceleration on Earth is
while on the Moon is 
, the ratio between the period on the Moon and on Earth is
where L is the pendulum length and g is the gravitational acceleration.
We can write down the ratio between the period of the pendulum on the Moon and on Earth by using this formula, and we find:
where the labels m and e refer to "Moon" and "Earth".
Since the gravitational acceleration on Earth is
Answer:
Maximum height of rocket = 2538.74 m
Explanation:
We have equation of motion s = ut + 0.5 at²
For first 5 seconds
s = 0 x 5 + 0.5 x 40 x 5² = 500 m
Now let us find out time after 5 seconds rocket move upward.
We have the equation of motion v = u + at
After 5 seconds velocity of rocket
v = 0 + 40 x 5 = 200 m/s
After 5 seconds the velocity reduces 9.8m/s per second due to gravity.
Time of flying after 5 seconds
Distance traveled in this 20.38 s
s = 200 x 20.38 - 0.5 x 9.81 x 20.38² = 2038.74 m
Maximum height of rocket = 500 +2038.74 = 2538.74 m