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2 years ago

Write a program that reads a floating-point number from the user and prints "zero", "positive" or "negative"

1 answer:

3 0

```
#!/usr/local/bin/python3

foo = float( input( "Enter a number: " ) )
if( foo < 0.0 ):
    print( "negative" )
elif( foo > 0.0 ):
    print( "positive" )
else
    print( "zero" )

exit( 0 )
```

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Answer:

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Explanation:

Given

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Required

Minimum number of servers needed

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Such that

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------------------------------------------------------------------------------------------------

<em>To get an expression for one server</em>

The probabilities of 1 servers having 99.98% reliability is as follows;

$p = 99.98\%$

Recall that probabilities always add up to 1;

So,

$p + q = 1$

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$1 - q^n = 99.98\%$

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$1 - q^n = \frac{9998}{10000}$

Convert fraction to decimal

$1 - q^n = 0.9998$

Add $q^n$ to both sides

$1 - q^n + q^n= 0.9998 + q^n$

$1 = 0.9998 + q^n$

Subtract 0.9998 from both sides

$1 - 0.9998 = 0.9998 - 0.9998 + q^n$

$1 - 0.9998 = q^n$

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From laws of logarithm $Loga^b = bLoga$

So,

$Log(0.0002) = Log(0.05^n)$ becomes

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Divide both sides by $Log0.05$

$\frac{Log(0.0002)}{Log(0.05)} = \frac{nLog(0.05)}{Log(0.05)}$

$\frac{Log(0.0002)}{Log(0.05)} = n$

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