Answer:
760 mm of Hg
Explanation:
If the gases A , B and C are non reacting , then according to <u>Dalton's </u><u>Law </u><u>of</u><u> </u><u>Partial </u><u>Pressure</u> the total pressure exerted is equal to sum of individual partial pressure of the gases .
If there are n , number of gases then ,
Here ,
- Partial pressure of Gas A = 400mm of Hg
- Partial pressure of Gas B = 220 mm of Hg
- Partial pressure of Gas C = 140mm of Hg
Hence the total pressure exerted is ,
Substitute ,

Add ,

<u>Hence</u><u> the</u><u> </u><u>total</u><u> pressure</u><u> exerted</u><u> by</u><u> the</u><u> </u><u>gases </u><u>is </u><u>7</u><u>6</u><u>0</u><u> </u><u>mm </u><u>of </u><u>Hg</u><u>.</u>
<em>I </em><em>hope</em><em> this</em><em> helps</em><em>.</em>
Answer:
C₆H₁₂O₆ + 6O₂ —> 6CO₂ + 6H₂O
Explanation:
Glucose (C₆H₁₂O₆) react with oxygen (O₂) to produce carbon dioxide (CO₂) and water (H₂O).
The equation can be written as follow:
C₆H₁₂O₆ + O₂ —> CO₂ + H₂O
The above equation can be balance as illustrated below:
C₆H₁₂O₆ + O₂ —> CO₂ + H₂O
There are 6 atoms of C on the left side and 1 atom on the right side. It can be balance by putting 6 in front of CO₂ as shown below:
C₆H₁₂O₆ + O₂ —> 6CO₂ + H₂O
There are 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H₂O as shown below:
C₆H₁₂O₆ + O₂ —> 6CO₂ + 6H₂O
There are a total of 8 atoms of O on the left side and a total of 18 atoms on the right side. It can be balance by 6 in front of O₂ as shown below:
C₆H₁₂O₆ + 6O₂ —> 6CO₂ + 6H₂O
Now, the equation is balanced.
Answer:
True!
Explanation:
Living things are classified by the characteristics they have in common. All living organisms are classified within the organization based on extremely fundamental, shared characteristics.
The energy that was released by the candy is calculates using the below formula
Q=Mc delta T
Q= heat energy
m= mass (500g)
C= specific heat capacity) = 4.18 j/g/c
delta t =change in temperature = 25- 21 = 4 c
Q= 500 g x 4.18 j/g/c x 4c = 8360 j
Answer:
8 moles
Explanation:
When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.
Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:
There are 8 moles in 272 grams of hydrogen peroxide.