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3 years ago

Please do this:) Thank you

Mathematics

2 answers:

sladkih [1.3K]3 years ago

5 0

Answer:

1) y = 12

2) x = 4

3) w = -3

4) k = -35

Step-by-step explanation:

aksik [14]3 years ago

3 0

Answer:

Question 1: y = 12

Question 2: x = 4

Question 3: w = -3

Question 4: k = -35

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Answer:

x= -2

Step-by-step explanation:

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3 years ago

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2 years ago

Read 2 more answers

Select the equation in slope-intercept form that is equivalent to: 4x + 3y = 12

sattari [20]

Answer:

y = -4/3x +4

Step-by-step explanation:

y= mx+b

solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

Let's solve for y.

4x+3y=12

Step 1: Add -4x to both sides.

4x+3y+−4x=12+−4x

3y=−4x+12

Step 2: Divide both sides by 3.

3y / 3 =-4x +12 /3

y = -4/3x +4

hopes this helps you out

5 0

3 years ago

DUE FIVE MINUTES HELPPPPPP!!!!!!!!!!!!!!!!

iris [78.8K]

Answer:

This is late you said it was due 5 min. yet I this was posted 5 hours. No one can help now.

Step-by-step explanation:

7 0

2 years ago

Find the inverse of ????−7 −2

Masja [62]

Answer:

$A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

Step-by-step explanation:

$A=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}$

$det\ A=-7\times 1-(-2)\times 4\\\Rightarrow det\ A=1$

$A^{-1}=\frac{1}{det\ A}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\frac{1}{1}\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$\therefore A^{-1}=\begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}$

$A.A^{-1}=\begin{bmatrix}-7 & -2\\ 4 & 1\end{bmatrix}\times \begin{bmatrix}1 & 2\\ -4 & -7\end{bmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}\left(-7\right)\cdot \:1+\left(-2\right)\left(-4\right)&\left(-7\right)\cdot \:2+\left(-2\right)\left(-7\right)\\ 4\cdot \:1+1\cdot \left(-4\right)&4\cdot \:2+1\cdot \left(-7\right)\end{pmatrix}\\\Rightarrow A.A^{-1}=\begin{pmatrix}1&0\\ 0&1\end{pmatrix}$

Hence, confirmed

6 0

3 years ago

Please do this:) Thank you​

Please do this:) Thank you