Part 1:
For this case we must see in the graph the axis of symmetry of the given parabola.
We have then that the axis of symmetry is the vertical line t = 2.
Answer:
The height of the javelin above the ground is symmetric about the line t = 2 seconds:
Part 2:
For this case, we must see the time t for which the javelin reaches a height of 20 feet for the first time.
We then have that when evaluating t = 1, the function is h (1) = 20. To do this, just look at the graph.
Then, we must observe the moment when it returns to be 20 feet above the ground.
For this, observing the graph we see that:
h (3) = 20 feet
Therefore, a height of 20 feet is again reached in 3 seconds.
Answer:
The javelin is 20 feet above the ground for the first time at t = 1 second and again at t = 3 seconds
Answer:
f = 10, g = 4.8 cm
Step-by-step explanation:
Area of ABCE = 60 cm²
Area of ABCD = 48 cm²
So,
Area of ADE = 60-48
=> 12 cm²
Area of ADE = 
<u><em>Where Area = 12 cm², Base = 4 cm</em></u>
12 = 
Height = 12-2
Height = 10 cm
Where Height is AD
So, AD = 10 cm
Also, <u><em>AD is parallel and equal to BC</em></u>
<u><em></em></u>
So,
f = 10 cm
<u><em>Now, Finding g</em></u>
Area of ABCD = 
<u><em>Where Area = 48 cm², Base = 10 cm</em></u>
48 = 10 * Height
Height = 48/10
Height = 4.8 cm
Whereas, Height is g
So, g = 4.8 cm
Answer:
Step-by-step explanation:
Answer:
60 minutes
Step-by-step explanation:
Let the number of minutes be represented as x
For Plan A
Plan A charges $35 plus $0.25 per minute for calls.
$35 + $0.25 × x
35 + 0.25x
For Plan B
Plan B charges $20 plus $0.50 per minute for calls.
$20 + $0.50 × x
20 + 0.50x
For what number of minutes do both plans cost the same amount?
This is calculated by equating Plan A to Plan B
Plan A = Plan B
35 + 0.25x = 20 + 0.50x
Collect like terms
35 - 20 = 0.50x - 0.25x
15 = 0.25x
x = 15/0.25
x = 60 minutes.
Hence, the number of minutes that both plans cost the same amount is 60 minutes
