In which type of wave do the particles in a medium move perpendicular to the direction that the wave moves?

You have a 1.8m long copper wire. You want to make an N-turn current loop that generates a 2.0mT magnetic field at the center wh

NikAS [45]

Answer:

The diameter is 0.022m.

Explanation:

The magnetic field $B$ at the center of the coil is given by

(1). $B = \dfrac{\mu_0 NI}{d}$

where $\mu_0 = 1.26*10^{-6} m\:kg\:s^{-2} A^{-2}$ is the magnetic constant, $I$ is the current, $N$ number of coils, and $d$ is the diameter of the coil.

Now, if we call $L$ the length of the wire, then it must be true that

$\pi dN = L$ (this says $N$ coil circumferences ( $c=\pi d$ ) fit into $L$ )

$\therefore N = \dfrac{L}{\pi d }$

putting this into equation (1) we get:

$B = \dfrac{\mu_0 IL }{\pi d^2}$

solve for $d:$

$\boxed{d = \sqrt{\dfrac{\mu_0I L }{\pi B} }}$

putting in the numerical values

$\mu_0 = 1.26*10^{-6} m\:kg\:s^{-2} A^{-2}$

$I =1.3A$

$L= 1.8m$

$B =2.0*10^{-3}T$

we get:

$d = \sqrt{\dfrac{(1.26*10^{-6})(1.3) *1.8 }{\pi (2.0*10^{-3})} }$

$\boxed{d = 0.022m}$

4 0

4 years ago

Will give 45 points to who ever solves this

Lubov Fominskaja [6]

Answer:

1. 230 kg...

W = m * g

W= 230 kg * 9.81 m/s^2

W= 2256,3 N

m= 230kg , W = 2256,3 N , g= 9.81 m/s^2

2. 887 N

W= m * g

887 N = m * 9.81 m/s^2

m= 90,42 kg

m= 90,42 kg, W = 887 N , g= 9.81 m/s^2

3. 420 kg

W= m * a

w= 420 kg * 9.81 m/s^2

w= 4120,2 N

m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2

4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.

w = m * g

55.5 N = 15 kg * g

a= 3,7 m/s^2

m = 15 kg , W= 55.5 N , g= 3,7 m/s^2

7 0

2 years ago

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Which is a negatively charged particle in an atom?

koban [17]

Answer:

electrons

Explanation:

electrons are negatively charged particles in an atom

3 0

3 years ago

A 920-kg sports car collides into the rear end of a 2300-kg SUV stopped at a red light. The bumpers lock, the brakes are locked,

GrogVix [38]

Answer:21.45 m/s

Explanation:

Given

Mass of sport car=920 kg

Mass of SUV=2300 kg

distance to which both car skid is 2.4 m

coefficient of friction ( $\mu$ )=0.8

Let u be the initial velocity of both car at the starting of skidding

and they finally come to zero velocity

$v^2-u^2=2as$

$acceleration=\mu g=0.8\times 9.8=7.84 m/s^2$

s=2.4 m

$0-(u)^2=2\times (-7.84)\times 2.4$

u=6.13 m/s

so before colliding sport car must be travelling at a speed of

$920\times v=(920+2300)\times 6.13$ (conserving momentum)

v=21.45 m/s

7 0

3 years ago

Another element is silvery-white with a shiny luster, is very brittle, and forms ions with a −2 charge. give one possible identi

Lesechka [4]

The element is magnesium ( Mg )

7 0

3 years ago

Read 2 more answers