Do it as if you are writing a yes or no statement but have edge more towards the no side.
<u>Answer:</u>
The ball fall vertically 2.69 ft by the time it reached home plate 60.0 ft away.
<u>Explanation:</u>
Fastest recorded pitches major-league baseball, thrown by nolan ryan in 1974 = 100.8 mi/hr = 44.8 m/s
The horizontal distance to home plate = 60.0 ft = 18.288 m
We have the horizontal velocity = 44.8 m/s
So time taken = 18.288/44.8 = 0.408 seconds.
The distance traveled by baseball vertically is found out by equation
Here u =0m/s, a = 9.81 and t = 0.408 s
Substituting
So vertical distance traveled = 0.82 m = 2.69 ft
Here, E<span>ach kilogram of mass weighs 9.8 newtons as it's unit value of it.
In short, Your Answer would be Option D
Hope this helps!</span>
Because weight W = M g, the ratio of weights equals the ratio of masses.
(M_m g)/ (M_w g) = [ (p^2 Man )/ (2 K_man)] / [ (p^2 Woman )/ (2 K_woman)
but p's are equal, so
K_m/K_m = (M_w g)/(M_m g) = W_woman / W_man = 450/680 = 0.662
Given:
h = 600 m, the height of descent
t = 5 min = 5*60 = 300 s, the time of descent.
Let a = the acceleration of descent., m/s².
Let u = initial velocity of descent, m/s.
Let t = time of descent, s.
The final velocity is v = 0 m/s because the helicopter comes to rest on the ground.
Note that u, v, and a are measured as positive upward.
Then
u + at = v
(u m/s) + (a m/s²)*(t s) = 0
u = - at
u = - 300a (1)
Also,
u*t + (1/2)at² = -h
(um/s)*(t s) + (1/2)(a m/s²)*(t s)² = 600
ut + (1/2)at² = 600 (2)
From (1), obtain
-300a +(1/2)(a)(90000) = -600
44700a = -600
a = - 1.3423 x 10⁻² m/s²
From (1), obtain
u = - 300*(-1.3423 x 10⁻²) = 4.03 m/s
Answer:
The acceleration is 0.0134 m/s² downward.
The initial velocity is 4.0 m/s upward.