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BARSIC [14]
3 years ago
13

Is it possible to calculate the displacement based on an elapsed time from a position time graph?

Physics
1 answer:
Nataly [62]3 years ago
5 0
No I don’t think so. But it worth a try tho. Try it out.
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Definition of graph?
xeze [42]

<u>Answer:</u>

1. A graph is defined as <em>" A Diagram represents a system of connections or interrelations among two or more things by a number of different dots, lines etc".</em>

2. In simple words <em>"Graph is a representation of any object or a physical structure by dots, lines, etc.</em>

6 0
3 years ago
A piece of metal will feel colder than a piece of wood at the same temperature. Why?
alexira [117]
Metals in general, are good heat conductors 
7 0
2 years ago
Use the following equation to help you answer the question. The peak intensity of radiation from a star named Sigma is 2 x 10 6
puteri [66]

Answer:

1449 K

Explanation:

The surface temperature of a star is related to its peak wavelength by Wien's displacement law:

T=\frac{b}{\lambda}

where

T is the surface temperature

b is Wien's displacement constant

\lambda=2\cdot 10^{-6} m

So the surface temperature of the star is

T=\frac{2.898 \cdot 10^{-3} Km}{2\cdot 10^{-6} m}=1449 K

8 0
3 years ago
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Why are body senses in psychology?
LUCKY_DIMON [66]

Answer: Body senses provide you with information about the position of your body in respect to your environment. The four main ones are touch, pain, vestibular, and kinesthesis.

More in details:

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7 0
2 years ago
Please help me with this question ASAP.
victus00 [196]

Answer:

i. 6.923 V

ii. The e.m.f. = 22.5 V

Explanation:

i. The given parameters are;

Length of potentiometer = 1 m

The resistance of the potentiometer = 10 Ω

The e. m. f. of the attached cell = 9 V

The current, I flowing in the circuit = e. m. f/(Total resistance)

The current, I flowing in the circuit = 9 V/(10 + 3) = 9/13 A

The potential difference, p.d. across the 1 m potentiometer wire = I × Resistance of the potentiometer wire

The p.d. across the potentiometer wire = 9/13×10 = 90/13 = 6.923 V

ii) Given that the 1 m potentiometer wire has a resistance of 10 Ω, 75 cm which is 0.75 m will have an e.m.f. given by the following relation;

\dfrac{E}{R_{balance}} = \dfrac{V}{R_{cell}}

Where:

E = e.m.f. of the balance point cell

R_{balance} = Resistance of 75 cm of potentiometer wire  = 0.75×10 = 7.5 Ω

R_{cell} = Resistance of the cell in the circuit = 3 Ω

V = e.m.f. attached cell = 9 V

\dfrac{E}{7.5} = \dfrac{9}{3}

E = 7.5*3 = 22.5 V

The e.m.f. = 22.5 V

7 0
3 years ago
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