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BARSIC [14]
3 years ago
13

Is it possible to calculate the displacement based on an elapsed time from a position time graph?

Physics
1 answer:
Nataly [62]3 years ago
5 0
No I don’t think so. But it worth a try tho. Try it out.
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Assuming 95.0% efficiency for the conversion of electrical power by the motor, what current must the 12.0-V batteries of a 708-k
Varvara68 [4.7K]

Answer:

a) I=646.9298\ A

b) I=1942.018\ A

Explanation:

Given:

  • efficiency of the motor, \eta=0.95
  • voltage of the battery, V=12\ V
  • mass of the car, m=708\ kg

a)

initial velocity, u=0\ m.s^{-1}

final velocity, v=25\ m.s^{-1}

time taken for the acceleration, t=1\ min=60\ s

Now we know by the Newton's second law of motion:

F=m.a

F=708\times \frac{(25-0)}{60}

F=295\ N

Now the power will be :

P=F.v

P=295\times 25

P=7375\ W

<u>According to the question:</u>

0.95 times of the electrical power should yield this mechanical power.

P=V.I\times 0.95

7375=12\times I\times 0.95

I=\frac{7375}{12\times 0.95}

I=646.9298\ A

b)

height climbed by the car, h=200\ m

velocity of climb, v=25\ m.s^{-1}

time taken to climb the height, t=2\ min=120\ s

force exerted to overcome air and frictional resistances, f=423\ N

Now the Power required to climb the hill:

P=\frac{m.g.h}{t} +f\times v

P=\frac{708\times 9.8\times 200}{120}+423\times 25

P=22139\ W

<u>Now according to the electrical efficiency:</u>

P=V.I\times 0.95

22139=12\times I\times 0.95

I=1942.018\ A

7 0
4 years ago
Read 2 more answers
Drag the tiles to the correct boxes to complete the pairs. Match each expression to its simplified form.
Naddik [55]

Answer:

3a^5 - (-a^5) = 3a^5 + a^5 = 4a^5

6a^7 - 2a^7 = 4a^7

-3a^5 - (-2a^5) = -3a^5 + 2a^5 = -a^5

7a^7 - 8a^7 = -a^7

7 0
3 years ago
Read 2 more answers
What is the electric force acting between two charges of 0.0072 C and -0.0060 C that are 0.0040 m apart?
telo118 [61]
Answer:
F = -2.4 * 10¹⁰ N

Explanation:
To get the electric force between two charges, we would use Coulomb's law which states that:
F = \frac{k * q1 * q2}{d^{2} }

where:
F is the force between the two charges
k is Coulomb's constant = 9 * 10⁹ Nm²/C²
q1 is the first charge = 0.0072 C
q2 is the second charge = -0.006 C
d is the distance between the two charges = 0.004 m

Substitute with the givens in the above formula to get the force between the two charges as follows:
F = \frac{9*10^9*0.0072*-0.006}{(0.004)^2}

F = -2.4 * 10¹⁰ N

Hope this helps :)
8 0
3 years ago
A body is moving along a circular path with variable speed, it has both radial and tangential acceleration.
belka [17]

Answer:

True;   ar = v^2 / R      Radial acceleration because it moves in a circular path

    at = α R = tangential acceleration because its speed changes

a = at + ar    total acceleration equals sum of radial and tangential

5 0
3 years ago
3. A car travelling at 20. m/s stops in a distance of 40. m. What is its
KIM [24]

Answer:

It was a joke i was getting the answer

Explanation:

Be percent karen

4 0
3 years ago
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