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Phantasy [73]
3 years ago
14

100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the

Chemistry
1 answer:
grandymaker [24]3 years ago
3 0

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

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Which of these particles are lost in the oxidation process? A. protons B. neutrons C. electrons D. atoms
vladimir2022 [97]

C. electrons

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3 years ago
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Which of the following choices represents a balanced chemical equation? A. Ca3(PO4)2 + 6SiO2 → P4O10 + 3CaSiO3 B. 2Ca3(PO4)2 + 6
Arturiano [62]

 the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

6 0
3 years ago
What is a sensory neuron?
ASHA 777 [7]

Answer: Nerve cells within the nervous system that are in charge of converting external stimuli from the organism's environment into internal electrical impulses.

4 0
3 years ago
A 10.00 mL sample of vinegar (an aqueous solution of acetic acid) is titrated with 0.5062 M NaOH(aq) and 16.58 mL is required to
sammy [17]

Answer:

5.01%

Explanation:

Density of vinegar = mass/volume

Mass of 10.00 mL = density x volume

                           = 1.006 x 10 = 10.06 g

From the equation of reaction:

CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)

1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.

mole of NaOH = molarity x volume

                      = 0.5062 x 0.01658

                       = 0.008392796‬ mole

0.008392796‬ mole of NaOH will therefore require 0.008392796‬ mole of CH3COOH.

mass of CH3COOH = mole x molar mass

                                     = 0.008392796‬ x 60.052

                                      = 0.504 g

Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%

    = 5.01%

The percent by mass of acetic acid in the vinegar is 5.01%

3 0
3 years ago
A scientist has 500 mL of a 2.1 M stock solution. She dilutes the solution, and the volume of the solution after the dilution is
Liono4ka [1.6K]

The molarity of the diluted solution is 0.32 M

Considering the question given above, the following data were obtained:

Volume of stock solution (V₁) = 500 mL

Molarity of stock solution (M₁) = 2.1 M

Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL

<h3>Molarity of diluted solution (M₂) =....? </h3>

The molarity of the diluted solution can be obtained as follow:

<h3>M₁V₁ = M₂V₂</h3>

2.1 × 500 = M₂ × 3250

1050 = M₂ × 3250

<h3>Divide both side by 3250</h3><h3 />

M₂ = 1050 / 3250

<h3>M₂ = 0.32 M</h3>

Therefore, the molarity of the diluted solution is 0.32 M

Learn more: brainly.com/question/22325751

4 0
2 years ago
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