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2 years ago

100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the

Chemistry

1 answer:

grandymaker [24]2 years ago

3 0

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

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Identify an element as a metal or a non-metal according to its position in the Periodic Table

Anestetic [448]

Answer:

Metals on the left of the Periodic Table.

Non-Metals on the top-right, plus Hydrogen.

4 0

2 years ago

Determine the volume of 3.30 mol of a gas at 25°C and 0.995 atm.

Alexxx [7]

Answer:

V = 81.14 L

Explanation:

Given data:

Volume of gas = ?

Number of moles = 3.30 mol

Temperature of gas = 25°C

Pressure of gas = 0.995 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

now we will put the values in formula:

V = 3.30 mol 0.0821 atm.L/ mol.K 298 K / 0.995 atm

V = 80.74 L. atm / 0.995 atm

V = 81.14 L

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3 years ago

The solubility product of PbI2 is 7.9x10^-9. What is the molar solubility of PbI2 in distilled water?

Agata [3.3K]

Answer: The molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

Explanation:

Solubility is defined as the maximum amount of solute that can be dissolved in a solvent at equilibrium.

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The balanced equilibrium reaction for the ionization of calcium fluoride follows:

$PbI_2\rightleftharpoons Pb^{2+}+2I^-$

s 2s

The expression for solubility constant for this reaction will be:

$K_{sp}=[Pb^{2+}][I^-]^2$

We are given:

$K_{sp}=7.9\times 10^{-9}$

Putting values in above equation, we get:

$7.9\times 10^{-9}=(s)\times (2s)^2\\\\7.9\times 10^{-9}=4s^3\\\\s=1.25\times 10^{-3}mol/L$

Hence, the molar solubility of $PbI_2$ is $1.25\times 10^{-3}mol/L$

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2 years ago

Why are people against saving the ozone layer?

nalin [4]

Because they don't care and think the ozone layer is fine.

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2 years ago

It is possiblefor an object's weight to change while its mass remains constan?Explain.

Georgia [21]

Answer:

Yes. Weight is the product of mass times gravitational acceleration. So all you have to do is vary the gravitational field and you vary weight.

Explanation:

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2 years ago