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3 years ago

100 ml is drawn from 0.1 M solution of KCl and added to 900 ml of water. What is the

Chemistry

1 answer:

grandymaker [24]3 years ago

3 0

Answer:

The new concentration will be 0.01 M.

Explanation:

To determine the new concentration we use the following formula.

concentration (1) × volume (1) = concentration (2) × volume (2)

concentration (1) = 0.1 M

volume (1) = 100 mL

concentration (2) = unknown

volume (2) = 100 mL + 900 mL = 1000 mL

concentration (2) = [concentration (1) × volume (1)] / volume (2)

concentration (2) = (0.1 × 100) / 1000 = 0.01 M

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Which of these particles are lost in the oxidation process? A. protons B. neutrons C. electrons D. atoms

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C. electrons

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Which of the following choices represents a balanced chemical equation? A. Ca3(PO4)2 + 6SiO2 → P4O10 + 3CaSiO3 B. 2Ca3(PO4)2 + 6

Arturiano [62]

the correct answer: 2Ca3(PO4)2 + 6SiO2 -> P4O10 + 6CaSiO3

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3 years ago

What is a sensory neuron?

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3 years ago

A 10.00 mL sample of vinegar (an aqueous solution of acetic acid) is titrated with 0.5062 M NaOH(aq) and 16.58 mL is required to

sammy [17]

Answer:

5.01%

Explanation:

Density of vinegar = mass/volume

Mass of 10.00 mL = density x volume

= 1.006 x 10 = 10.06 g

From the equation of reaction:

$CH_3COOH(aq)+NaOH(aq)-->CH_3COONa(aq)+H_2O(l)$

1 mole pf CH3COOH requires 1 mole of NaOH for neutralization.

mole of NaOH = molarity x volume

= 0.5062 x 0.01658

= 0.008392796‬ mole

0.008392796‬ mole of NaOH will therefore require 0.008392796‬ mole of CH3COOH.

mass of CH3COOH = mole x molar mass

= 0.008392796‬ x 60.052

= 0.504 g

Percentage by mass of acetic acid in the vinegar = 0.504/10.06 x 100%

= 5.01%

The percent by mass of acetic acid in the vinegar is 5.01%

3 0

3 years ago

A scientist has 500 mL of a 2.1 M stock solution. She dilutes the solution, and the volume of the solution after the dilution is

Liono4ka [1.6K]

The molarity of the diluted solution is 0.32 M

Considering the question given above, the following data were obtained:

Volume of stock solution (V₁) = 500 mL

Molarity of stock solution (M₁) = 2.1 M

Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL

<h3>Molarity of diluted solution (M₂) =....? </h3>

The molarity of the diluted solution can be obtained as follow:

2.1 × 500 = M₂ × 3250

1050 = M₂ × 3250

<h3>Divide both side by 3250</h3><h3 />

M₂ = 1050 / 3250

Therefore, the molarity of the diluted solution is 0.32 M

Learn more: brainly.com/question/22325751

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2 years ago