Answer:
the thermal energy generated in the loop = 
Explanation:
Given that;
The length of the copper wire L = 0.614 m
Radius of the loop r = 
r = 
r = 0.0977 m
However , the area of the loop is :



Change in the magnetic field is 
Then the induced emf e = 
e = 
e = 2.74 × 10⁻³ V
resistivity of the copper wire
Ω m
diameter of the wire = 1.08 mm
radius of the wire = 0.54 mm = 0.54 × 10⁻³ m
Thus, the resistance of the wire R = 
R = 
R = 1.13× 10⁻² Ω
Finally, the thermal energy generated in the loop (i.e the power) = 
= 
= 
Answer:
false 20 n x 0.32 m = 6.4 J
Newtons first law states that an object will remain still or in straight line. Until acted upon some force!
Answer:
7500 N/m²
Explanation:
From the question given above, the following data were obtained:
Force (F) = 300 N
Area (A) = 400 cm²
Pressure (P) =?
Next, we shall convert 400 cm² to m². This can be obtained as follow:
1×10⁴ cm² = 1 m²
Therefore,
400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²
400 cm² = 0.04 m²
Finally, we shall determine the pressure. This can be obtained as follow:
Force (F) = 300 N
Area (A) = 0.04 m²
Pressure (P) =?
P = F/A
P = 300 / 0.04
P = 7500 N/m²