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Elodia [21]
3 years ago
15

If someone drops a cup, it falls to the ground. Why doesn't the gravitational force between the person's hand and the cup keep t

he cup from falling?
Physics
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

The gravity from the person's hand is weaker than the gravity from the pull of the earth

Explanation:

The gravity from the person's hand is weaker than the gravity from the pull of the earth

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Four 5-gram blocks of metal are sitting out in the sun and absorb the same amount of heat energy. Use the following specific hea
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Answer:

There is NO DATA??

Explanation:

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If 61.4 cm of copper wire (diameter = 1.08 mm, resistivity = 1.69 × 10-8Ω·m) is formed into a circular loop and placed perpendic
harkovskaia [24]

Answer:

the thermal energy generated in the loop = 6.64*10^{-4}  \ W

Explanation:

Given that;

The length of the copper wire L = 0.614 m

Radius of the loop  r = \frac{L}{2 \pi}

r = \frac{0.614}{2 \pi}

r = 0.0977 m

However , the area of the loop is :

A_L = \pi r^2

A_L = \pi (0.0977)^2

A_L = 0.02999 \ m^2

Change in the magnetic field is \frac{dB}{dt}= 0.0914 \ T/s

Then the induced emf e = A_L \frac{dB}{dt}

e = 0.02999 * 0.0914

e = 2.74 × 10⁻³ V

resistivity of the copper wire \rho = 1.69* 10^{-8} Ω m

diameter of the wire = 1.08 mm

radius of the wire = 0.54 mm = 0.54 × 10⁻³  m

Thus, the resistance of the wire  R = \frac {\rho L}{\pi r^2}

R =  \frac{(1.69*10^{-8})(0.614)}{   \pi (0.54*10^{-3})^2}

R = 1.13× 10⁻² Ω

Finally,  the thermal energy generated in the loop (i.e the power) = \frac{e^2}{R}

= \frac{(2.74*10^{-3})^2}{1.13*10^{-2}}

= 6.64*10^{-4}  \ W

8 0
3 years ago
If an object that weighs 20 N is lifted from the ground to a
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3 0
4 years ago
What is Newtens first law of motion​
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Newtons first law states that an object will remain still or in straight line. Until acted upon some force!

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If the area of a concrete slap weighing 300n is 400cm2 ,how much pressure can it apply when kept on the ground
aleksklad [387]

Answer:

7500 N/m²

Explanation:

From the question given above, the following data were obtained:

Force (F) = 300 N

Area (A) = 400 cm²

Pressure (P) =?

Next, we shall convert 400 cm² to m². This can be obtained as follow:

1×10⁴ cm² = 1 m²

Therefore,

400 cm² = 400 cm² × 1 m² / 1×10⁴ cm²

400 cm² = 0.04 m²

Finally, we shall determine the pressure. This can be obtained as follow:

Force (F) = 300 N

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Pressure (P) =?

P = F/A

P = 300 / 0.04

P = 7500 N/m²

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3 years ago
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