KE = 1/2 x 80 x 60^2
KE = 144000
Big band is music group (a group of people who perform instrumental and/or vocal music ) playing jazz or jazz-influenced popular music and which was popular during the Swing Era from the mid-1930s until the late 1940s. These big bands contained saxophones, trumpets, trombone and other instruments and typically consisted of approximately 12 to 25 musicians.
Answer:
The magnetic field strength inside the solenoid is
.
Explanation:
Given that,
Radius = 2.0 mm
Length = 5.0 cm
Current = 2.0 A
Number of turns = 100
(a). We need to calculate the magnetic field strength inside the solenoid
Using formula of the magnetic field strength
Using Ampere's Law
![B=\dfrac{\mu_{0}NI}{l}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B%5Cmu_%7B0%7DNI%7D%7Bl%7D)
Where, N = Number of turns
I = current
l = length
Put the value into the formula
![B=\dfrac{4\pi\times10^{-7}\times100\times2.0}{5.0\times10^{-2}}](https://tex.z-dn.net/?f=B%3D%5Cdfrac%7B4%5Cpi%5Ctimes10%5E%7B-7%7D%5Ctimes100%5Ctimes2.0%7D%7B5.0%5Ctimes10%5E%7B-2%7D%7D)
![B=0.005026=5.026\times10^{-3}\ T](https://tex.z-dn.net/?f=B%3D0.005026%3D5.026%5Ctimes10%5E%7B-3%7D%5C%20T)
(b). We draw the diagram
Hence, The magnetic field strength inside the solenoid is
.
Answer:
![\alpha = 6.431\,\frac{rad}{s^{2}}](https://tex.z-dn.net/?f=%5Calpha%20%3D%206.431%5C%2C%5Cfrac%7Brad%7D%7Bs%5E%7B2%7D%7D)
Explanation:
The pulley is modelled by the Newton's Laws, whose equation of equilibrium is:
![\Sigma M = T \cdot R = \frac{1}{2}\cdot M \cdot R^{2}\cdot \alpha](https://tex.z-dn.net/?f=%5CSigma%20M%20%3D%20T%20%5Ccdot%20R%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20M%20%5Ccdot%20R%5E%7B2%7D%5Ccdot%20%5Calpha)
Given that tension is equal to the weight of the bucket, the angular acceleration experimented by the pulley is:
![T = \frac{1}{2}\cdot M \cdot R \cdot \alpha](https://tex.z-dn.net/?f=T%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20M%20%5Ccdot%20R%20%5Ccdot%20%5Calpha)
![m_{b}\cdot g = \frac{1}{2}\cdot M \cdot R \cdot \alpha](https://tex.z-dn.net/?f=m_%7Bb%7D%5Ccdot%20g%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20M%20%5Ccdot%20R%20%5Ccdot%20%5Calpha)
![\alpha = \frac{2\cdot m_{b}\cdot g}{M\cdot R}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B2%5Ccdot%20m_%7Bb%7D%5Ccdot%20g%7D%7BM%5Ccdot%20R%7D)
![\alpha = \frac{2\cdot (1.53\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}{(7.07\,kg)\cdot (0.66\,m)}](https://tex.z-dn.net/?f=%5Calpha%20%3D%20%5Cfrac%7B2%5Ccdot%20%281.53%5C%2Ckg%29%5Ccdot%20%5Cleft%289.807%5C%2C%5Cfrac%7Bm%7D%7Bs%5E%7B2%7D%7D%20%5Cright%29%7D%7B%287.07%5C%2Ckg%29%5Ccdot%20%280.66%5C%2Cm%29%7D)
![\alpha = 6.431\,\frac{rad}{s^{2}}](https://tex.z-dn.net/?f=%5Calpha%20%3D%206.431%5C%2C%5Cfrac%7Brad%7D%7Bs%5E%7B2%7D%7D)
Answer:
his is an example of the transformation of gravitational potential energy into kinetic energy
Explanation:
The game of juggling bowling is a clear example of the conservation of mechanical energy,
when the bolus is in the upper part of the path mechanical energy is potential energy; As this energy descends, it becomes kinetic energy where the lowest part of the trajectory, just before touching the hand, is totally kinetic.
At the moment of touching the hand, a relationship is applied that reverses the value of the speed, that is, now it is ascending and the cycle repeats.
Therefore this is an example of the transformation of gravitational potential energy into kinetic energy