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The net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
To find the answer, we have to know more about the basic forces acting on a body.
<h3>How to find the net force on the box?</h3>- Let us draw the free body diagram of the given box with the data's given in the question.
- From the diagram, we get,
where, N is the normal reaction, mg is the weight of the box, is the net force, f is the kinetic friction.
- We have the expression for kinetic friction as,
- Thus, the net force will be,
Thus, we can conclude that, the net force acting on the box of mass 1.75kg when it is pushed across a ground with coefficient of friction k=0.267 with a force of 8.35N, is 3.77N.
Learn more about the basic forces on a body here:
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