Is there any other information given? I don't think you can solve this without a time
Answer:
body position 4 is (-1,133, -1.83)
Explanation:
The concept of center of gravity is of great importance since in this all external forces are considered applied, it is defined by
x_cm = 1 /M ∑ 
m_{i}
y_cm = 1 /M ∑ y_{i} mi
Where M is the total mass of the body, mi is the mass of each element
give us the mass and position of this masses
body 1
m1 = 2.00 ka
x1 = 0 me
y1 = 0 me
body 2
m2 = 2.20 kg
x2 = 0m
y2 = 5 m
body 3
m3 = 3.4 kg
x3 = 2.00 m
y3 = 0
body 4
m4 = 6 kg
x4=?
y4=?
mass center position
x_cm = 0
y_cm = 0
let's apply to the equations of the initial part
X axis
M = 2.00 + 2.20 + 3.40
M = 7.6 kg
0 = 1 / 7.6 (2 0 + 2.2 0 + 3.4 2 + 6 x4)
x4 = -6.8 / 6
x4 = -1,133 m
Axis y
0 = 1 / 7.6 (2 0 + 2.20 5 +3.4 0 + 6 y4)
y4 = -11/6
y4 = -1.83 m
body position 4 is (-1,133, -1.83)
F = ma
<span>where </span>
<span>F = frictional force </span>
<span>m = mass of the block = 1.4 kg (given) </span>
<span>a = acceleration of the block = 1.25 m/sec^2 (given) </span>
<span>Substituting values, </span>
<span>F = (1.4)(1.25) </span>
<span>F = 1.75 N </span>
<span>By definition, </span>
<span>F = (mu)(Normal force) </span>
<span>where </span>
<span>mu = coefficient of friction </span>
<span>Normal force = mg = 1.4*9.8 = 13.72 </span>
<span>Again, substituting appropriate values, </span>
<span>1.75 = mu(13.72) </span>
<span>mu = 0.128</span>
Answer:
- <em><u>This section assumes you have enough background in calculus to be familiar with integration. In Instantaneous Velocity and Speed and Average and Instantaneous Acceleration we introduced the kinematic functions of velocity and acceleration using the derivative. By taking the derivative of the position function we found the velocity function, and likewise by taking the derivative of the velocity function we found the acceleration function. Using integral calculus, we can work backward and calculate the velocity function from the acceleration function, and the position function from the velocity function.</u></em>
Explanation:
<h3>Derive the kinematic equations for constant acceleration using integral calculus.</h3><h3>Use the integral formulation of the kinematic equations in analyzing motion.</h3><h3>Find the functional form of velocity versus time given the acceleration function.</h3><h3>Find the functional form of position versus time given the velocity function.</h3>
Answer:
8.2 mm / day * 1 m / 1000 mm = .00082 m / day distance in 1 day
365 day / 1 yr * .00082 m / day = .30 m / yr
