All categories

3 years ago

PLS ANSWER FAST WILL GIVE BRANLEST!!!

Physics

2 answers:

nevsk [136]3 years ago

7 0

$\huge\bf{\pink{\underline{\underline{\mathcal{AnSwer࿐}}}}}$

<h2>Given:- </h2>

acceleration = 1000 m/s²
force = 5000 N

Mass of the cannonball

<h2>Formula to be used:- </h2>

$\longrightarrow$ $\underline{\boxed{\sf mass = \dfrac{force}{acceleration}}}$

<h2>Solution:- </h2>

: $\implies$ $\sf mass = \dfrac{5000}{1000}$

: $\implies$ $\sf mass = 5 kg$

hence, the required answer is 5kg.

melamori03 [73]3 years ago

4 0

Answer:

mass=force/acceleratio

m=5000/1000

m=5kg

You might be interested in

A motorcycle begins at rest and accelerates uniformly S7.9 we want to find a time to take the motorcycle to reach a speed of 100

Len [333]

The motorbike reaches 100 km/h in 3.5 seconds

Explanation:

The motion of the motorbike is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:

$v=u+at$

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the time

For the motorbike in this problem,

u = 0 (it starts from rest)

$v = 100 km/h = 27.8 m/s$ is the final velocity

$a=7.9 m/s^2$ is the acceleration

Solving for t, we find the time it takes for the bike to reach that velocity:

$t=\frac{v-u}{a}=\frac{27.8-0}{7.9}=3.5 s$

Learn more about accelerated motion:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

brainly.com/question/2562700

#LearnwithBrainly

6 0

3 years ago

A negative charge is at rest at the origin of an axis system. Location x is at coordinate point (2m,3m) while location y is at (

Sergeu [11.5K]

The magnitude of the E-field decreases as the square of the distance from the charge, just like gravity.

Location ' x ' is √(2² + 3²) = √13 m from the charge.

Location ' y ' is √ [ (-3)² + (-2)² ] = √13 m from the charge.

The magnitude of the E-field is the same at both locations.

The direction is also the same at both locations ... it points toward the origin.

5 0

3 years ago

What effect does the vertical acceleration have on the horizontal velocity of the projectile?

KengaRu [80]

Answer:
None, if air resistance is ignored.

Explanation:
At any instant, the projectile has vertical and horizontal components of velocity.
Vertical acceleration due to gravity affects the vertical velocity by accelerating the object toward the center of the earth, and by decreasing the upward vertical velocity..
The horizontal component of velocity makes the object travel horizontally as long as the projectile is airborne.
Thsi discussion assumes that air resistance is ignored.

3 0

3 years ago

Car A has a mass of 1,200 kg and is traveling at a rate of 22 km/hr. It collides with car B. Car B has a mass of 1,900 kg and is

anastassius [24]

The car A has a mass of 1200 kg.

The car B has the mass of 1900 kg.

It is given that velocity of car A is given as 22 Km/hr

The car B has the velocity of 25 Km/hr.

Let the mass of two bodies are denoted as $m_{1} \ and\ m_{2}$

Let the velocity of cars A and B are denoted as $v_{1} \ and\ v_{2}$

The momentum before collision is-

$p_{i} =m_{1} v_{1} +m_{2} v_{2}$

[Here p stand for momentum.]

We are asked to calculate the final momentum of the system after collision.

The answer of the question is based law of conservation of linear momentum.

As per law of conservation of linear momentum the sum total linear momentum for an isolated system is always constant.Hence irrespective of the type of collision[elastic and inelastic],the momentum of the system is always constant which is a universal truth.

Let after the collision the velocity of A and B are $v'_{1} \ and\ v'_{2}$