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Alja [10]
3 years ago
6

When cooking food in a microwave, why is it more important to rely on the internal temperature of the food rather than on a prev

ious cooking time?
Physics
2 answers:
SSSSS [86.1K]3 years ago
7 0
When cooking food in a microwave it is more important to rely on the internal temperature of the food because microwave do not adequately kills pathogens that may be in food.  Microwave normally penetrate food to the depth of 1 to 1.5 only. In thicker foods, microwave doesn't usually reach the center of the food, the un-reached part normally cook by conduction.
goldenfox [79]3 years ago
7 0

Relying on <u>internal temperature is more important</u> when cooking food in a microwave rather than on previous cooking time because the internal temperature of the food is a critical indicator if the food is safe for consumption.

<h2>Further Explanation  </h2>

Microwave

Microwave has a generator inside it that is called magnetron. This magnetron gets electricity from the power outlet and convert this into radio waves. The magnetron then shoots these waves into the food compartment. The molecules of the food absorbs the energy causing them to vibrate and move fast. The higher the kinetic energy the hotter the temperature of the substance. Basically, it is just ENERGY transfer.

Internal temperature vs. cooking time

When cooking raw meat and poultry, food handlers must ensure that the food’s internal temperature has reached the safe minimum temperature and rest time. A food thermometer must be used to check the temperature. When roasting, the oven temperature must not be lower than 325 °F. Cooking to a safe minimum cooking temperature destroys harmful bacteria that cause food borne illness.  

<u>Safe Minimum internal Temperature and Rest Time for Meat  </u>

  • Poultry (All poultry, minced, whole, chopped and stuffing) - 165ºF  
  • Beef, Pork, Veal, and Lamb (chops, roasts, steaks) - 145ºF with a 3 minute rest time  
  • Minced Meat - 160ºF  

<u />

<u>Danger Zone</u> (40 ℉ - 140 ℉) is the range of temperature where it is very ideal for harmful bacteria to grow rapidly.

Learn more:

  1. Convection brainly.com/question/2480283
  2. Danger Zone brainly.com/question/4496421

Keywords: microwave, internal temperature, cooking

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Calculate the location xcm of the center of mass of the Earth-Moon system. Use a coordinate system in which the center of the Ea
Jet001 [13]

Answer:

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

Explanation:

Let suppose that planet and satellite can be treated as particles. The masses of Earth and Moon (m_{E}, m_{M}) are 5.972\times 10^{24}\,kg and 7.349\times 10^{22}\,kg, respectively. The distance between centers is 384,403 kilometers. The location of the center of mass can be found by using weighted averages:

\bar x = \frac{x_{E}\cdot m_{E}+x_{M}\cdot m_{M}}{m_{E}+m_{M}}

If x_{E} = 0\,km and x_{M} = 384,403\,km, then:

\bar x = \frac{(0\,km)\cdot (5.972\times 10^{24}\,kg)+(384,403\,km)\cdot (7.349\times 10^{22}\,kg)}{5.972\times 10^{24}\,kg+7.349\times 10^{22}\,kg}

\bar x = 4.673\,km

The center of mass of the Earth-Moon system is 4.673 kilometers away from center of Earth.

8 0
3 years ago
How much kinetic energy does a 1500 kg car have if it’s moving at 15 m/s
Tresset [83]

Answer:

Mass of car m = 1500 kg

velocity v = 15 m/s

kinetic energy = ½ mv2

= ½ x 1500 x (15)2    

= 1687501   kg m2 /s2

  = 168750J

Explanation:

6 0
3 years ago
1. A listener stands 20.0 m from a speaker that pumps out music with a power output of 100.0 W.
marta [7]

(1.a) The surface area being vibrated by the time the sound reaches the listener is 5,026.55 m².

(1.b) The intensity of the sound wave as it reaches the person listening is 0.02 W/m².

(1.c) The relative intensity of the sound as heard by the listener is 103 dB.

(2.a) The speed of sound if the air temperature is 15⁰C is 340.3 m/s.

(2.b) The frequency of the sound heard by the suspect is 614.3 Hz.

<h3>Surface area being vibrated</h3>

The surface area being vibrated by the time the sound reaches the listener is calculated as follows;

A = 4πr²

A = 4π x (20)²

A = 5,026.55 m²

<h3>Intensity of the sound</h3>

The intensity of the sound is calculated as follows;

I = P/A

I = (100) / (5,026.55)

I = 0.02 W/m²

<h3>Relative intensity of the sound</h3>

B = 10log(\frac{I}{I_0} )\\\\B = 10 \times log(\frac{0.02}{10^{-12}} )\\\\B = 103 \ dB

<h3>Speed of sound at the given temperature</h3>

v= 331.3\sqrt{1 + \frac{T}{273} } \\\\v = 331.3\sqrt{1 + \frac{15}{273} } \\\\v = 340.3 \ m/s

<h3>Frequency of the sound</h3>

The frequency of the sound heard is determined by applying Doppler effect.

f_o = f_s(\frac{v \pm v_0}{v \pm v_s} )

where;

  • -v₀ is velocity of the observer moving away from the source
  • -vs is the velocity of the source moving towards the observer
  • fs is the source frequency
  • fo is the observed frequency
  • v is speed of sound

f_0 = f_s(\frac{v-v_0}{v- v_s} )

f_0 = 512(\frac{340.3 - 10}{340.3 - 65} )\\\\f_0 = 614.3 \ Hz

Learn more about intensity of sound here: brainly.com/question/17062836

3 0
2 years ago
Imagine an infinite earth with a hole dripped through it. You fall in and accelerate at g~10m/s/s. How long until you reach the
Soloha48 [4]

An object with non-zero mass (even negligible mass is non-zero) will never reach the speed of light. Due to relativistic effects, each "unit" of acceleration becomes less effective at increasing your velocity (relative to some other object, of course) as your relative velocity approaches the speed of light.

And even if there was a way, If you would accelerate to the 99,99% of the speed light in just 1 second, you would experience a G-force of aprox. 30,600,000 g's which is enough to kill you in a few seconds

6 0
3 years ago
A 10-m-long glider with a mass of 680 kg (including the passengers) is gliding horizontally through the air at 34 m/s when a 60
german

Answer:

34 m/s

Explanation:

m = Mass of glider with person = 680 kg

v = Velocity of glider with person = 34 m/s

m_1 = Mass of glider without person = 680-60 kg

v_1 = Gliders speed just after the skydiver lets go

m_2 = Mass of person = 60 kg

v_2 = Velcotiy of person = 34 m/s

As the linear momentum of the system is conserved

m_1v_1+m_2v_2=mv\\\Rightarrow v_1=\dfrac{mv-m_2v_2}{m_1}\\\Rightarrow v_1=\dfrac{680\times 34-60\times 34}{680-60}\\\Rightarrow v_1=34\ m/s

The gliders speed just after the skydiver lets go is 34 m/s

3 0
3 years ago
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