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Marina CMI [18]
3 years ago
11

So, what is the answer of this assignment?

Physics
1 answer:
Ket [755]3 years ago
6 0
What assignment, you have to work with me here i don't know what were working on
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A tow truck is pulling 25,000 kg van with a tow hook that meets the van at an angle of 30° with the ground. How much force must
Law Incorporation [45]

Answer:

86605.08 N

Explanation:

The equation to calculate the force is:

Force = mass * acceleration

The force and the acceleration does not have the same direction in this case, so we need to decompose the force into its horizontal component, which is the force that will generate the horizontal acceleration:

Force_x = Force * cos(30)

Then, we have that:

Force_x = mass * acceleration

Force * cos(30) = 25000 * 3

Force * 0.866 = 75000

Force = 75000 / 0.866 = 86605.08 N

3 0
3 years ago
A box is at rest on a ramp at an incline of 22°. The normal force on the box is 538 N.
fomenos

Answer: 580 N

Refer to attached figure.

The angle of inclination is 22 degrees

weight (gravitational force) acts downwards.

Normal force is a contact force which acts perpendicular to the point of contact.

The horizontal component (mg cos 22 ) balances the normal force and the vertical component balances the frictional force.

Gravitational force on an object = mg

The normal force N= mg cos 22

\Rightarrow mg =\frac{N}{cos22}=\frac{538 N}{0.927}=580 N





8 0
3 years ago
Read 2 more answers
At what angle torque is half of the max
denis-greek [22]
At what angle torque is half of max
8 0
3 years ago
A 9.6 cm diameter circular loop of wire is in a 1.10 T magnetic field perpendicular to the plane of the loop. The loop is remove
Natali5045456 [20]

Answer:

Thus induced emf is 0.0531 V

Solution:

As per the question:

Diameter of the loop, d = 9.6\ cm = 0.096\ m

Thus the radius of the loop, R = 0.048 m

Time in which the loop is removed, t = 0.15 s

Magnetic field, B = 1.10 T

Now,

The average induced emf, e is given by Lenz Law:

e = - \frac{\Delta \phi_{B}}{\Delta t}

e = - \frac{\Delta \phi_{B}}{\Delta t}

where

\phi_{B} = magnetic flux = A\Delta B

where

A = cross sectional area

Also, we know that:

e = - \frac{A\Delta B}{\Delta t}

e = - \frac{\pi r^{2}\times (0 - 1.10)}{0.15}

e = - \frac{\pi \times 0.048^{2}\times (0 - 1.10)}{0.15}

e = 0.0531 V

The sketch is shown in the figure, where I indicates the direction of the induced current.

3 0
3 years ago
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Help please...............
Slav-nsk [51]
According to the given passage,
Over exposure to UV rays causes skin damage or even cancer.

(If you need further explanation) 
Over exposure to UV rays also causes Sunburn (or erythema); is redness of the skin, which is due to increased blood flow in the skin caused by dilatation of the superficial blood vessels in the dermis. High UV doses may also results in edema, pain, blistering, and peeling of the skin a few days following exposure. Other effects includes Suppression of the Immune System, <span>Damage to the Eyes, etc.</span>
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