Question

A diver who is 10.0 m underwater experiences a pressure of 202 kPa. If the diver's surface area is 1.50 m.sq, with how much total force does water push on the driver?

Answer 1

The pressure on the diver is given by:

$p=\frac{F}{A}$

where F is the force exerted by the water on the diver, while A is the area of the diver.

In this problem, we know the pressure: $p=202 kPa=2.02 \cdot 10^5 Pa$, and the area of the diver, $A=1.50 m^2$, therefore we can rearrange the initial equation to find the force on the diver:

$F=pA=(2.02 \cdot 10^5 Pa)(1.50 m^2)=3.03 \cdot 10^5 N$

Answer 2

We know that:
Pressure = Force / Area
Force = Pressure x Area
Force = 202,000 x 1.5
Force = 303,000 Newtons