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marissa [1.9K]
3 years ago
14

The organ procurement and transplant network (OPTN) was established by?

Physics
2 answers:
damaskus [11]3 years ago
5 0
The answer to that would be A. the national organ transplant Act of 1984 the goals of the OPTN  are to increase the number of and access to transplants, improve survival rates after transplantation, and to promote patient safety and efficient management of the system.
nikklg [1K]3 years ago
5 0

Answer: A. National Organ Transplant Act of 1984

Explanation: The National Organ Transplant Act of 1984 established the Organ Procurement and Transplant Network (OPTN), a national system to address fair allocation of organs for transplant. Patients on the waiting list are in end-stage organ failure and have been evaluated by a transplant physician at U.S. hospitals where organ transplants are performed.

The OPTN is operated by the nonprofit United Network for Organ Sharing (UNOS). UNOS committees and a board of directors composed of transplant physicians, government officials, immunology specialists, organ donation experts, donor families, transplant recipients, and members of the public have created rules for organ allocation.

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Answer:

t = 2.58*10^-6 s

Explanation:

For a nonconducting sphere you have that the value of the electric field, depends of the region:

rR:\\\\E=k\frac{Q}{r^2}

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R: radius of the sphere = 10.0/2 = 5.0cm=0.005m

In this case you can assume that the proton is in the region for r > R. Furthermore you use the secon Newton law in order to find the acceleration of the proton produced by the force:

F=m_pa\\\\qE=m_pa\\\\k\frac{qQ}{r^2}=m_pa\\\\a=k\frac{qQ}{m_pr^2}

Due to the proton is just outside the surface you can use r=R and calculate the acceleration. Also, you take into account the charge density of the sphere in order to compute the total charge:

Q=\rho V=(5.5*10^{-6}C/m^3)(\frac{4}{3}\pi(0.05m)^3)=2.87*10^{-9}C\\\\a=(8.98*10^9Nm^2/C^2)\frac{(1.6*10^{-19}C)(2.87*10^{-9}C)}{(1.67*10^{-27}kg)(0.05m)^2}=9.87*10^{11}\frac{m}{s^2}

with this values of a you can use the following formula:

a=\frac{v-v_o}{t}\\\\t=\frac{v-v_o}{a}=\frac{2550*10^3m/s-0m/s}{9.87*10^{11}m/s^2}=2.58*10^{-6}s

hence, the time that the proton takes to reach a speed of 2550km is 2.58*10^-6 s

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2 years ago
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Answer:

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