First thing you have to do is change your coordinate system so that you’re perpendicular with the surface. So your weight vector will have a horizontal and vertical component. I’m going to try to do this in my head. I usually make a free body diagram. So we only want the horizontal net force because we aren’t asked about the vertical. The horizontal component of the weight vector would be opposite of the angle. So you’re gonna have to use sine instead of cosine.
Wx = W*sin(230)
To find the weight, multiply the mass by gravity. It will be 9.8N
Wx = 9.8N*sin230
Wx = -7.5i
The weight component is the only force on system, horizontally.
So do -7.5N = 1kg(a)
a = -7.5m/s^2
And you should know that acceleration is equal to the velocity over time.
-7.5 = Velocity/2s
Velocity = -15m/s
Again, sorry if I’m wrong. Did this all in my head
Hole up your right hand like you're holding a glass of water and point with your thumb in the direction the current is travelling through the wire the rest of your fingers indicate the magnetic field lines direction
<h3><u>Answer;</u></h3>
Migration
<h3><u>Explanation; </u></h3>
- Migration is the movement of animals from one place to another. Migration is an innate behavior that is triggered by changes in the environment.
- For example, animals may migrate when the days get shorter in the fall. Migration is most common in birds, fish, and insects.
- The regular movement of animals takes place at certain period each year, for the purposes of finding food, mates, or other resources.
During it's upward motion, gravity acts on the ball which points towards the center of the earth. Since displacement of ball and force are in opposite direction, work done on ball while going up is negative.
During it's downward motion, gravity acts on the ball which points towards the center of the earth. Since displacement of ball and force are in same direction, work done on ball while coming down is positive.
Hi there!
We can begin by calculating the distance remaining after the reaction time.
Δd = vt
Calculate the distance traveled within this time:
Δd = (16)(.79) = 12.64 m
Subtract from the total distance:
150 - 12.64 = 137.66 m remaining
We can use the following equation to solve for the acceleration necessary:
vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.
Rearrange in terms of "a":
0 = vi² + 2ad
(-vi²) = 2ad
(-vi²)/2d = a
Plug in the given values:
(-(16²))/2(137.66) = a
-256/275.32 = -.9298 m/s²
