Answer
given,
frequency from Police car= 1240 Hz
frequency of sound after return = 1275 Hz
Calculating the speed of the car = ?
Using Doppler's effect formula
Frequency received by the other car
..........(1)
u is the speed of sound = 340 m/s
v is the speed of the car
Frequency of the police car received

now, inserting the value of equation (1)


1.02822(340 - v) = 340 + v
2.02822 v = 340 x 0.028822
2.02822 v = 9.799
v = 4.83 m/s
hence, the speed of the car is equal to v = 4.83 m/s
Because it increases cardiorespiratory fitness and means that one has a strong heart and circulatory system. This results in being able to avoid heart disease and other dangerous diseases or disorders. Additionally, exercise can help our mental health along with maintaining weight and staying physically healthy.
Answer:
Average speed of car in the first trip is 10 km/hr
Explanation:
It is given that first the car drives 6 hours to the east
Then travels 12 km to west in 3 hours
Average speed for the entire trip = 8 km/hr
Total time = 3+6 = 9 hour
So distance traveled in 9 hour = 9×8 = 72 km
As the car travel 12 km in west so distance traveled in east = 72-12 = 60 km
Time by which car traveled in east = 6 hour
So speed 
So average speed of car in the first trip is 10 km/hr
Answer:
B) Tommy had a positive acceleration between noon and 12:30 pm.
Explanation:
Acceleration is defined as the rate of change of velocity:

where
v is the final velocity
u is the initial velocity
t is the time
In the problem,
- At noon, Tommy is walking at a velocity of 4 mi/h
- At 12.30 pm, Tommy is walking at a velocity of 6 mi/h
- A time of half an hour (0.5 h) passed between the two moments
So Tommy's acceleration is

and the acceleration is positive, since the velocity has increased.
A useful formula that gives the free-fall distance from rest in 'T' seconds:
D = (1/2 G) x (T²)
G = 9.81 m/s²
1/2 G = 4.905 m/s²
D (5 seconds) = (4.905 m/s²) x (5 sec)²
= (4.905 m/s²) x (25 sec²)
= 122.625 meters .
Since the tower-top is 100m above ground,
the depth of the well, to the top of the water,
accounts for the additional 22.625 meters.
My question is: How do you know exactly when the stone hit the water ?
You probably stood at the top of the well and listened for the
sound of the 'plop'. But it took some time after the stone hit
the water for the sound of the plop to come back up to you.
Well, can't you just subtract that time ? Yes, but you need
to know how much time to subtract. That depends on the
depth of the well ... which is exactly what you're trying to
determine, so you don't know it yet.
Oh well. That's a deep subject.