There is no movement in line C and the greatest velocity occurs at line D. The answers are:
1. 0.5 m/s
2. 0.25 m/s
3. 14m and -2m
4. -1 m/s
<h3>
What is Position - time Graph ?</h3>
Position time graph is the graph of distance or displacement against time. The slope of the graph is velocity.
The given positions of four objects as a function of time are shown
on the graph to the right.
1.) The velocity of object A will be the slope m of the line A.
Slope m = Δx / Δt
m = (4 - 0) / (8 - 0)
m = 4 / 8
m = 0.5 m/s
Velocity at A = 0.5 m/s
2.) The average velocity of object B will be the slope m of the line B.
Slope m = Δx / Δt
m = (6 - 4) / (8 - 0)
m = 2 / 8
m = 0.25 m/s
The average velocity of object B is 0.25s
3.) The object moved a total distance during the first eight seconds will be 4m for A, 2m for B, and 8m for D
Total distance = 4 + 2 + 8 = 14m
It’s net displacement during the same time will be 2. That is,
Displacement = 8 - 6 = -2m
4.) The greatest speed occurred at line D. The velocity of the object moving at the greatest speed will be the slope of the line D
V = -Δx / Δt
V = -8/8
V = -1 m/s
Therefore, there is no movement in line C and the greatest velocity occurs at line D.
Learn more about velocity time graph here :brainly.com/question/769606
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Let car A's starting position be the origin, so that its position at time <em>t</em> is
A: <em>x</em> = (40 m/s) <em>t</em>
and car B has position at time <em>t</em> of
B: <em>x</em> = 100 m - (60 m/s) <em>t</em>
<em />
They meet when their positions are equal:
(40 m/s) <em>t</em> = 100 m - (60 m/s) <em>t</em>
(100 m/s) <em>t</em> = 100 m
<em>t</em> = (100 m) / (100 m/s) = 1 s
so the cars meet 1 second after they start moving.
They are 100 m apart when the difference in their positions is equal to 100 m:
(40 m/s) <em>t</em> - (100 m - (60 m/s) <em>t</em>) = 100 m
(subtract car B's position from car A's position because we take car A's direction to be positive)
(100 m/s) <em>t</em> = 200 m
<em>t</em> = (200 m) / (100 m/s) = 2 s
so the cars are 100 m apart after 2 seconds.
Answer:
A car accelerates from rest, and travels 400 m in 3.5 seconds. If
the net force on the car is 12,000 N what is the mass of the car? bzgs dvd d dv dvdvd dhd dbvd
Explanation:
shd dhd bdvd dhdbduhdbdhdbbdceudd f
Gravity affects weight of an object
Its weight reduces as it moves away from the center as gravity is strongest near the core and reduces as you move away
Hope this helps C:
