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4 years ago

How does a lever work?(awarding 24pts for immediate answer!!!!)

2 answers:

8 0

Levers overcome a resistance when a force is applied. They have a fixed support to which they freely turn, called the fulcrum. In some levers, it is possible to increase speed by applying the force over a shorter distance than the resistance is moved. A proportional increase of force is needed for this.

vlada-n [284]4 years ago

6 0

It's a simple machine, consisting of a rigid bar that rotates about a fixed point which is known as "Fulcrum" (most important part), It <span>affects the effort, or force and do the amount of work

Hope this helps!</span>

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A block (mass m1) lying on a frictionless inclined plane is connected to a mass (mass m2) by a massless cord passing over a pull

azamat

Answer:

a) System aceleration:

$a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}$

b) Direction of movement:

The block $m_1$ down the plane when the acceleration is negative. This occur when:

$m_2-m_1sin(\theta)$

The block $m_2$ up the plane when the acceleration is positive. This occur when:

$m_2-m_1sin(\theta)>0$

Explanation:

For the block $m_1$ the move direction is parallel (||) to the plane

$\sum F_{||}=m_1a=T-sin(\theta)mg$ (1)

For the block $m_2$ the move direction is vertical (y)

$\sum F_y=m_2a=m_2g-T$ (2)

Both blocks are connected with the same cable, therefore, the tension on the cable and the acceleration is the same for both.

Solving the equation 2 for T:

$T=m_2g-m_2a$ (3)

replacing (3) in the equation (1)

$m_2g-m_2a- m_1gsin(\theta)=m_1a$ (4)

solving (4) for a:

$a=\frac{g(m_2-m_1sin(\theta))}{m_1+m_2}$

8 0

3 years ago

Does an object which is positively charged contains all protons and no electrons?

Aleonysh [2.5K]

Answer:

Positively charged objects have electrons; they simply possess more protons than electrons.

Explanation:

2. An object that is electrically neutral contains only neutrons. Electrically neutral atoms simply possess the same number of electrons as protons.

<h3>Information:</h3>

If an atom has an equal number of protons and electrons, its net charge is 0. If it gains an extra electron, it becomes negatively charged and is known as an anion.

If it loses an electron, it becomes positively charged and is known as a cation.

<h2>I hope this answers help you! :></h2>

7 0

3 years ago

Read 2 more answers

What does increasing the impulse on an object due to its momentum?

allochka39001 [22]

increaskng the impulse also <u>increases </u><u>momentum</u>

7 0

2 years ago

Help<br> help <br> help<br> plssss

Flauer [41]

Answer:

sorry i don't no

i promise i will help you later

now i am also in trouble now

nobody helps me

4 0

3 years ago

A ball is dropped from rest at a point 12 m above the ground into a smooth, frictionless chute. The ball exits the chute 2 m abo

Nonamiya [84]

Answer:

29,7 m

Explanation:

We need to devide the problem in two parts:

A) Energy

B) MRUV

<u>Energy:</u>

Since no friction between pint (1) and (2), then the energy conservatets:

Energy = constant ----> Ek(cinética) + Ep(potencial) = constant

Ek1 + Ep1 = Ek2 + Ep2

Ek1 = 0 ; because V1 is zero (the ball is "dropped")

Ep1 = m*g*H1

Ep2= m*g*H2

Then:

Ek2 = m*g*(H1-H2)

By definition of cinetic energy:

m*(V2)²/2 = m*g*(H1-H2) ---> $V2 = \sqrt{(2*g*(H1-H2)}$

Replaced values: V2 = 14,0 m/s

The decomposition of the velocity (V2), gives a for the horizontal component:

V2x = V2*cos(α)

Then the traveled distance is:

X = V2*cos(α)*t.... but what time?

The time what takes the ball hit the ground.

Since: Y3 - Y2 = V2*t + (1/2)*(-g)*t²

In the vertical axis:

Y3 = 0 ; Y2 = H2 = 2 m

Reeplacing:

-2 = 14*t + (1/2)*(-9,81)*t²

solving the ecuation, the only positive solution is:

t = 2,99 sec ≈ 3 sec

Then, for the distance:

X = V2*cos(α)*t = (14 m/s)*(cos45°)*(3sec) ≈ 29,7 m

6 0

4 years ago

Read 2 more answers