The various contributions involved till the chapati is made is given below.
<h3>What is food?</h3>
The substance that we intake for the body to charge up by giving nutrients is called the food.
Wheat is a staple food. We make chapati from flour obtained from the wheat grains.
The various contributions involved till the chapati is made is given below.
Take required amount of atta in a container
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Add water accordingly to form a dough
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Apply oil to make dough smooth for long time
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Take small dough, make it a ball shaped and apply dry flour
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Roll it using rolling pin on the chapati maker plate
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After making it circular or any shape you want, place it on hot tawa
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Bake it on both the sides
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Chapati is ready
Thus, the flow chart is made.
Learn more about food.
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Answer:The correct options are:
1. A system is a group of objects analyzed as one unit.
2. Energy that moves across system boundaries is conserved.
Explanation:
A system is defined as group of interrelated or interacting items existing as a single unit or a whole to achieve a specific objective.Energy lost by the system is equal to the energy gained by the surroundings.
Two statements are true about a system:
- A system is a group of objects analyzed as one unit.
- Energy that moves across system boundaries is conserved.
The difference in the pressure between the inside and outside will be 369.36 N/m²
<h3>What is pressure?</h3>
The force applied perpendicular to the surface of an item per unit area across which that force is spread is known as pressure.
It is denoted by P. The pressure relative to the ambient pressure is known as gauge pressure.
The given data in the problem is;
dP is the change in the presure=?
Using Bernoulli's Theorem;

Hence, the difference in the pressure between the inside and outside will be 369.36 N/m²
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Answer:
(a) work required to lift the object is 1029 J
(b) the gravitational potential energy gained by this object is 1029 J
Explanation:
Given;
mass of the object, m = 35 kg
height through which the object was lifted, h = 3 m
(a) work required to lift the object
W = F x d
W = (mg) x h
W = 35 x 9.8 x 3
W = 1029 J
(b) the gravitational potential energy gained by this object is calculated as;
ΔP.E = Pf - Pi
where;
Pi is the initial gravitational potential energy, at initial height (hi = 0)
ΔP.E = (35 x 9.8 x 3) - (35 x 9.8 x 0)
ΔP.E = 1029 J
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