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Tom [10]
3 years ago
11

How does the force block A exerts on block B compare to the force block B exerts on block A?

Physics
1 answer:
s344n2d4d5 [400]3 years ago
6 0

Answer:

too much force

Explanation:

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A student is preparing to take a bath when she realizes the hot water tap in the bathroom is not working the student go to the k
WITCHER [35]

Answer:

The final temperature of the bath water will be 55°C

Explanation:

A student is preparing to take a bath when she realizes that the hot water tap is not working.

The student goes to the kitchen and prepares 10 L of 100 degree Celsius water to mix with 10 L of 10 degree Celsius water. What will be the final temperature of the bath water?

Using the relation, Heat lost  = Heat gained (assuming no heat is lost to the surroundings).

Heat lost by hot water = heat gained by cold water

Using the formula of heat, Q = mcΔT

where m = mass of water, c = specific heat capacity of water, ΔT = temperature difference

mass of water = density * volume (density of water = 1 kg/L)

mass of hot water, m₁ = 1 kg/L * 10 L = 10 kg;

mass of cold water, m₂ = 1 kg/L * 10 L = 10 kg;

specific heat capacity of water, c = 4200 j/kg

Let the final temperature of the mixture be T

-m₁cΔT₁ = m₂cΔT₂ ( since heat is lost by the hot water)

-m₁ΔT₁ = m₂ΔT₂

-10 * (T- 100) = 10 * (T - 10)

-10T + 1000 = 10T - 100

20T = 1100

T = 1100/20

T = 55°C

Therefore, the final temperature of the bath water will be 55°C

6 0
3 years ago
Give examples of friction being useful and not useful in everyday life
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The same strength force was exerted in the same direction on both Object A and Object B. Why did Object A go faster than Object
VashaNatasha [74]

Answer:

m_B > m_A

the mass of body B must be greater than the mass of body A

Explanation:

Newton's second law establishes a linear relationship between the force, the mass of the body and its acceleration

        F = m a

        a = F / m

Let's analyze this expression tells us that the force is of equal magnitude for the two bodies, but body A goes faster than body B, this implies that it has more relationships

         a_A > a_B

         \frac{F}{m_A} > \frac{F}{m_B}

         m_B > m_A

Therefore, for this to happen, the mass of body B must be greater than the mass of body A

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