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4 years ago

Which reaction takes place in a nuclear fission reactor?

Chemistry

2 answers:

Aleonysh [2.5K]4 years ago

7 0

Answer:

It’s C I think Explanation:

djverab [1.8K]4 years ago

7 0

Answer:

It's B

Explanation:

In a fission reaction, a larger nucleus is split into two more stable nuclei.

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What is the molarity of 3.0 L solution containing 250 g of Nal

IgorC [24]

Answer: C. 0.57 M

Explanation:

Molarity= Moles/Vol

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3 years ago

What is a substance's specific heat? the energy required to raise one kilogram of the substance one degree the energy required t

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the energy required to raise one kilogram of the substance one degree

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4 years ago

Can snow have viscosity?

iren [92.7K]

Answer: Yes

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3 years ago

Read 2 more answers

Magnesium metal burns in air to form a mixture of magnesium oxide (MgO, M = 40.31) and magnesium nitride (Mg3N2, M = 100.95). A

dedylja [7]

Answer:

26.95 %

Explanation:

Air contains the highest percentage of oxygen and nitrogen gases. Magnesium then combines with both of the gases:

$2 Mg (s) + O_2 (g)\rightarrow 2 MgO (s)$

$3 Mg (s) + N_2 (g)\rightarrow Mg_3N_2 (s)$

Firstly, find the total number of moles of magnesium metal:

$n_{Mg} = \frac{1.000 g}{24.305 g/mol} = 0.041144 mol$

Let's say that x mol react in the first reaction and y mol react in the second reaction. This means:

$x + y = 0.041144 mol$

According to stoichiometry, we form:

$n_{MgO} = x mol, n_{Mg_3N_2} = \frac{y}{3} mol$

Multiplying moles by the molar mass of each substance will yield mass. This means we form a total of:

$m_{MgO} = 40.31x g, m_{Mg_3N_2} = \frac{y}{3} 100.95 g =$

The total mass is given, so we have our second equation to solve:

$40.31x + 33.65y = 1.584$

We have two unknowns and two equations, we may then solve:

$x + y = 0.041144$

$40.31x + 33.65y = 1.584$

Express y from the first equation:

$y = 0.041144 - x$

Substitute into the second equation:

$40.31x + 33.65(0.04144 - x) = 1.584$

$40.31x + 1.39446 - 33.65x = 1.584$

$6.66x = 0.18954$

$x = 0.028459$

$y = 0.041144 - x = 0.012685$

Moles of nitride formed:

$n_{Mg_3N_2} = \frac{y}{3} = 0.0042282 mol$

Convert this to mass:

$m_{Mg_3N_2} = 0.0042282 mol\cdot 100.95 g/mol = 0.4268 g$

Find the percentage:

$\omega_{Mg_3N_2} = \frac{0.4268 g}{1.584 g}\cdot 100\% = 26.95 \%$

7 0

3 years ago

:answer question number 6

solong [7]

Answer: C?

Explanation:

5 0

3 years ago