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jonny [76]
2 years ago
15

The specific heat of aluminum is 0.900 J/g*°C, the specific heat of air is 1.01 J/g*°C and the specific heat of iron is 0.450 J/

g*°C.
Identify the correct statement.

Air requires the most energy to increase its temperature followed by iron and then aluminum.
Iron requires the most energy to increase its temperature followed by aluminum and then air.
Air requires the most energy to increase its temperature followed by aluminum and then iron.
Iron requires the most energy to increase its temperature followed by air and then aluminum.
Chemistry
1 answer:
artcher [175]2 years ago
7 0

The correct statement regarding the specific heat capacity of the substance is as follows: air requires the most energy to increase its temperature followed by aluminum and then iron.

<h3>What is specific heat capacity?</h3>

Specific heat capacity of a substance refers to the amount of thermal energy required to raise the temperature of a system by one temperature unit (1°C or 1K) without any change of phase.

According to this question, the specific heat of different elements are as follows:

  1. Aluminum = 0.900 J/g°C
  2. Air = 1.01 J/g°C
  3. Iron = 0.450 J/g°C

Therefore, it can be said that air requires the most energy to increase its temperature followed by aluminum and then iron.

Learn more about specific heat at: brainly.com/question/13145357

#SPJ1

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During decomposition of water,10g of oxygen gas was formed.How much hydrogen gas was formed
statuscvo [17]

Answer:

https://www.quora.com/The-following-chemical-reaction-shows-the-decomposition-of-water-to-form-hydrogen-gas-and-oxygen-gas-2H2O-I-produces-2H2-g-O2-g-if-10-0-grams-of-water-reacted-and-you-found-1-11-grams-of-H2-formed-how-many-of-O2

Explanation: i hope ths helps you

8 0
3 years ago
Write the balanced molecular chemical equation for the reaction
Ierofanga [76]

The balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

  • For any chemical equation to be balanced, the number of moles of elements in the reactants must be equal to that of the product.

  • According to the question, we are to write a balanced equation for the reaction  in aqueous solution for cesium carbonate and magnesium  nitrate
  • The chemical formula for Cesium carbonate is Cs₂CO₃
  • The chemical formula for magnesium  nitrate is Mg(NO₃)₂

Hence the balanced molecular chemical equation for the reaction will be expressed as Cs₂CO₃ + Mg(NO₃)₂ -> 2CsNO₃ + MgCO₃

Learn more here: brainly.com/question/11904811

4 0
3 years ago
Read 2 more answers
how much water should be added to 1 gallon of pure antifreeze to obtain a solution that is 60% antifreeze?
antoniya [11.8K]
1 gallon of antifreeze = 60% of mixture. Total mixture:
Vm = 1/0.6
= 1.67 gallons

Volume of water = total vol - antifreeze vol
= 1.67 - 1
= 0.67 gallon of water
7 0
3 years ago
What is 10 times as many as 1 hundred is blank hundred or blank thousand ?
Rama09 [41]

10 times as many as 1 hundred is 10 hundred or 1 thousand.

This is the question of simple multiplications related to a place value system.

The given equation in unit form can be rewritten as:

10 × 1 × 100 = (X × 100) or (Y × 1000)

Arranging in two parts, we get,

10 × 1 × 100 = X × 100           ........(1)

10 × 1 × 100 = Y × 1000         ........(2)

Now, calculating the value of X and Y,

From equation (1), we get,

10 × 1 × 100 = X×100

or, 1000 = X × 100

or, X = 10

Hence, 10 times as many as 1 hundred is 10 hundred.

Similarly, from equation (2). we get,

10 × 1 × 100 = Y × 1000

or, 1000 = Y × 1000

or, Y = 1

Hence, 10 times as many as 1 hundred is 1 thousand.

Therefore, 10 times as many as 1 hundred is 10 hundred or 1 thousand.

To learn more about hundreds, thousands, and place values, visit: brainly.com/question/17785584

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8 0
1 year ago
A buffer is prepared by adding 139 mL of 0.39 M NH3 to 169 mL of 0.19 M NH4NO3. What is the pH of the final solution? (Assume th
Paha777 [63]

Answer:

pH = 9.48

Explanation:

We have first to realize that NH₃ is a weak base:

NH₃ + H₂O ⇔ NH₄⁺ + OH⁻     Kb = 1.8 x 10⁻⁵

and we are adding this weak base to a solution of NH₄NO₃ which being a salt dissociates 100 % in water.

Effectively what we have here is a buffer of a weak base and its conjugate acid. Therefore, we need the Henderson-Hasselbach formula for weak bases given by:

pOH = pKb + log ( [ conjugate acid ] / [  weak base ]

mol NH₃ = 0.139 L x 0.39 M = 0.054 mol

mol NH₄⁺ = 0.169 L x 0.19 M = 0.032 mol

Now we have all the information required to calculate the pOH ( Note that we dont have to calculate the concentrations since in the formula they are a ratio and the volume will cancel out)

pOH = -log(1.8 x 10⁻⁵) + log ( 0.032/0.054) = 4.52

pOH + pH = 14 ⇒ pH = 14 - 4.52 = 9.48

The solution is basic which agrees  with NH₃ being  a weak base.

5 0
3 years ago
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