Answer:
Scientists interpret data based on their background knowledge and experience; thus, different scientists can interpret the same data in different ways.
Therefore the answer to your question is
<h2><u>True</u><u>.</u></h2>
<em><u>Hop</u></em><em><u>e</u></em><em><u> this</u></em><em><u> helps</u></em><em><u> you</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
<em><u>Hop</u></em><em><u>e</u></em><em><u> you</u></em><em><u> have</u></em><em><u> a</u></em><em><u> nice</u></em><em><u> day</u></em><em><u> ahead</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
The molarity of the diluted solution is 0.32 M
Considering the question given above, the following data were obtained:
Volume of stock solution (V₁) = 500 mL
Molarity of stock solution (M₁) = 2.1 M
Volume of diluted solution (V₂) = 3.25 L = 3.25 × 1000 = 3250 mL
<h3>Molarity of diluted solution (M₂) =....? </h3>
The molarity of the diluted solution can be obtained as follow:
<h3>M₁V₁ = M₂V₂</h3>
2.1 × 500 = M₂ × 3250
1050 = M₂ × 3250
<h3>Divide both side by 3250</h3><h3 />
M₂ = 1050 / 3250
<h3>M₂ = 0.32 M</h3>
Therefore, the molarity of the diluted solution is 0.32 M
Learn more: brainly.com/question/22325751
Answer:
D
Explanation:
D. V1P1 / T1=V2P2 / T2 is correct
The new concentrations of 
and 
are 0.25M and 19M
Calculation of number of moles of each component,
Molarity of = number of moles/volume in lit = 0. 500 M
Number of moles = molarity of × volume in lit = 0. 500 M× 0.025 L
Number of moles of = 0.0125 mole
Molarity of = number of moles/volume in lit = 0. 38 M
Number of moles = molarity of × volume in lit = 0. 38 M× 0.025 L
Number of moles of = 0.95 mole
Calculation of new concentration at volume 50 ml ( 0.05L)
Molarity of = number of moles/volume in lit = 0.0125 mole/0.05L
Molarity of = 0.25M
Molarity of = number of moles/volume in lit = 0.95mole/0.05L
Molarity of = 19 M
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