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Bad White [126]
3 years ago
14

What is the mass (in grams) of 9.27x1024 molecules of methanol(CH3OH)

Chemistry
2 answers:
garri49 [273]3 years ago
5 0
Moles of methanol = 9.27x10^24/6.02x10^23 = 15.398 moles.

Mass of methanol = moles of methanol x molar mass of methanol
                               = 15.398 x 32.042
                               = 493.38 grams.

Hope this helps!

seropon [69]3 years ago
4 0

Answer:  493 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadro's number}}=\frac{9.27\times 10^{24}}{6.023\times 10^{23}}=15.4moles

1 mole of CH_3OH weighs = 32 g

15.4 moles of CH_3OH weigh = \frac{32}{1}\times 15.4=493g

Thus mass of 9.27\times 10^{24} molecules of methanol weigh 493 grams.

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Answer:

Given equation of parabola is

and

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The point at which the tangent to the curve is parallel to the line is the nearest point on the curve.

On differentiating both sides of equation (i), we get

2 y

dx

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d y

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Also, slope of the given line is −

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From equation (i), (−24)

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3 years ago
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<u>Answer:</u> The mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

<u>Explanation:</u>

We are given:

A chemical compound having chemical formula of C_8H_9NO_2. This compound is made by the combination of carbon, hydrogen, nitrogen and oxygen elements.

1 mole of acetaminophen contains 8 moles of carbon atom, 9 moles of hydrogen atom, 1 mole of nitrogen atom and 2 moles of oxygen atom

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Mass of hydrogen element = (9\times 1)=9g/mol

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Mass of oxygen element = (2\times 16)=32g/mol

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To calculate the percentage composition of an element in a compound, we use the equation:

\%\text{ composition of an element}=\frac{\text{Mass of element}}{\text{Mass of compound}}\times 100      ........(1)

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Putting values in equation 1, we get:

\% \text{ composition of carbon element}=\frac{96}{151}\times 100\\\\\% \text{ composition of carbon element}=63.57\%

  • <u>For hydrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of hydrogen element}=\frac{9}{151}\times 100\\\\\% \text{ composition of hydrogen element}=5.96\%

  • <u>For nitrogen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of nitrogen element}=\frac{14}{151}\times 100\\\\\% \text{ composition of nitrogen element}=9.28\%

  • <u>For oxygen element:</u>

Putting values in equation 1, we get:

\% \text{ composition of oxygen element}=\frac{32}{151}\times 100\\\\\% \text{ composition of oxygen element}=21.19\%

Hence, the mass percentage of carbon element is 63.57 %, hydrogen element is 5.96 %, nitrogen element is 9.28 % and oxygen element is 21.19 %

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