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Bad White [126]
3 years ago
14

What is the mass (in grams) of 9.27x1024 molecules of methanol(CH3OH)

Chemistry
2 answers:
garri49 [273]3 years ago
5 0
Moles of methanol = 9.27x10^24/6.02x10^23 = 15.398 moles.

Mass of methanol = moles of methanol x molar mass of methanol
                               = 15.398 x 32.042
                               = 493.38 grams.

Hope this helps!

seropon [69]3 years ago
4 0

Answer:  493 grams

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text{Avogadro's number}}=\frac{9.27\times 10^{24}}{6.023\times 10^{23}}=15.4moles

1 mole of CH_3OH weighs = 32 g

15.4 moles of CH_3OH weigh = \frac{32}{1}\times 15.4=493g

Thus mass of 9.27\times 10^{24} molecules of methanol weigh 493 grams.

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