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meriva
2 years ago
7

How many ions are in 32.45 grams of silver carbonate

Chemistry
1 answer:
GuDViN [60]2 years ago
4 0

Answer:

0.0036265350669622

Explanation:

Report if wrong

-Atlas-

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How many grams of oxygen can be obtained from 250. grams of KCIO3?
guapka [62]

Answer:

Keep it simple. If all the oxygen contained in the 200 grams of potassium chlorate is produced in the decomposition, then all we have to do is find out how many grams of oxygen are there in the 200 grams. This we can do by calculating the ratio of oxygen mass to the whole. Using 39.1 for potassium, 35.45 for chlorine and 3 times 16, or 48 for the oxygen, we get a total of 122.55 grams per mole for potassium chlorate, of which 48 grams are oxygen. This ratio is 48/122.55. This ratio times the original 200 grams of the compound, gives us 78.34 grams of oxygen produced.

Explanation:

3 0
2 years ago
Ionization of sodium dichromate​
inessss [21]

Explanation:

this is the answer of your question .

hope it helped you

5 0
2 years ago
A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /
Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

t_{1} = 25 °C

t_{2} = 36,4 °C

Q = 325 J

The formula is: Q = c * m * (t_{2} - t_{1})

m = \frac{Q}{c * (t_{2} - t_{1} )}

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0
3 years ago
Which is a difference between global and local winds?
valentina_108 [34]

Explanation:

local winds are considered breezes while global winds produce mostly storms

3 0
3 years ago
A standard 10.00 g mass is weighed on an analytical balance 100 times. The average and standard deviation obtained gives 10.12 ±
Mekhanik [1.2K]

Answer:

There was an improvement in accuracy. There was no change in precision.

Explanation:

<em>The average mass after recalibration is closer to the mass of the standard, </em>so the recalibration improved the accuracy<em> </em>(the measurement is closer to an accepted 'true' value).

The standard deviation did not change, so the precision (or how disperse the measurements are) was not affected.

5 0
3 years ago
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