To solve this problem it is necessary to apply the equations related to the Force of Friction and Energy.
By definition the friction force is defined as
Where,
Frictional Constant
N = Normal Force -> mg
At the same time we have the definition of the Energy, which can be
E = F*v
Where,
Force
v = Velocity.
Then replacing with our values we have that,
F = 0.5 *34
F = 17
The energy then would be,
E = f v
E = 17 * 0.30 = 5.1 W
Therefore the rate at which heat is generated is 5.1W
Answer
given,
L(t) = 10 - 3.5 t
mass of particle = 2 Kg
radius of the circle = 3.1 m
a) torque
τ =
τ =
τ = -3.5 N.m
Particle rotates clockwise as i look down the plane. Hence, its angular velocity is downward.
L decreases the angular acceleration upward. so, net torque is upward.
b) Moment of inertia of the particle
I = m R^2
I = 2 x 3.1²
I = 19.22 kg.m²
L = I ω
ω =
ω =
ω =
A = 0.52 rad/s B = -0.182 rad/s²
Answer:
(a) T = 0.015 N
(b) M = 1.53 x 10⁻³ kg = 1.53 g
Explanation:
(a) T = 0.015 N
First, we will find the speed of waves:
where,
v = speed of wave = ?
f = frequency = 120 Hz
λ = wavelength = 6 cm = 0.06 m
Therefore,
v = (120 Hz)(0.06 m)
v = 7.2 m/s
Now, we will find the linear mass density of the coil:
where,
μ = linear mass density = ?
m = mass = 1.45 g = 1.45 x 10⁻³ kg
l = length = 5 m
Thereforre,
Now, for the tension we use the formula:
<u>T = 0.015 N</u>
<u></u>
(b)
The mass to be hung is:
<u>M = 1.53 x 10⁻³ kg = 1.53 g</u>