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12345 [234]
3 years ago
5

On a cold day you can warm your hands by rubbing them together. (a) Assume that the coefficient of friction between your hands i

s 0.5, that the normal force between your hands is 34 N, and that you rub them together at an average speed of 30 cm/s. What is the rate at which heat is generated?
Physics
1 answer:
melomori [17]3 years ago
6 0

To solve this problem it is necessary to apply the equations related to the Force of Friction and Energy.

By definition the friction force is defined as

F= \mu * N

Where,

\mu = Frictional Constant

N = Normal Force -> mg

At the same time we have the definition of the Energy, which can be

E = F*v

Where,

Force

v = Velocity.

Then replacing with our values we have that,

F = \mu N

F = 0.5 *34

F = 17

The energy then would be,

E = f v

E = 17 * 0.30 = 5.1 W

Therefore the rate at which heat is generated is 5.1W

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Mr. White claims that he invented a heat engine with a maximum efficiency of 90%. He measured the temperature of the hot reservo
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Answer:

The error he made was that he didn't convert the unit of temperature to Kelvin.

The correct efficiency is 24%

Explanation:

Parameters given:

Temperature of hot reservoir = 100°C = 373 K

Temperature of cold reservoir = 10°C = 273 K

The efficiency of a heat engine is given as:

E = 1 - (Qc/Qh) = 1 - (Tc/Th)

Where

Qc = Output heat;

Qh = Input heat;

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Th = Temperature of the hot reservoir.

=> E = 1 - (283/373)

E = 1 - 0.76

E = 0.24

In percentage,

E = 0.24 * 100 = 24%

Hence, the efficiency of the engine is actually 24%.

The error he made was that he didn't convert the temperature to Kelvin. If we leave the temperatures in °C, we have that:

E = 1 - (10/100)

E = 1 - 0.1 = 0.9

In percentage,

E = 0.9 * 100 = 90%

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