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3 years ago

PSYCHOLOGY QUESTION

Physics

2 answers:

Anna71 [15]3 years ago

7 0

Answer:

Some anxiety disorders have different symptoms and it is important to figure out how those symptoms develop. Symptoms may develop from physiological, psychological, or environmental influences. Physiological factors may include heredity, chemical and hormonal imbalances, gender (females are more prone to anxiety than males), and anxiety sensitivity, which has to do with how one’s body reacts to chemical changes. Psychological influences focus on how one’s mind reacts to fearful situations. Environmental factors also influence how individuals deal with fearful situations. Environmental stress levels, how we think or interpret situations, and our observations of how others react to similar situations all impact how we manage anxiety.

Explanation:

Julli [10]3 years ago

3 0

Answer:

Not sure what yours looking for but When a disease is widespread, epidemiological studies investigate what associated factors, such as location, swx, exposure to chemicals and many others, make a population more or less likely to have an illness, condition, or disease thus helping determine its etiology.

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Find the net force on Each box

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1. 40 n

2. 25 n

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A 750 kg car is moving at 20.0 m/s at a height of 5.0 m above the bottom of a hill when it runs out of gas. From there, the car

S_A_V [24]

Answer:

Explanation:

Kinetic energy at the height = 1/2 m v²

= 1/2 x 750 x 20²

= 150000 J

Its potential energy = mgh

= 750 x 9.8 x 5

=36750 J

Total energy = 186750 J

Its total kinetic energy will be equal to 186750 J , according to conservation of mechanical energy

If v be its velocity at the bottom

1/2 m v² = 186750

v = √498

= 22.31 m /s

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3 years ago

At high noon, the sun delivers 1150 w to each square meter of a blacktop road. if the hot asphalt loses energy only by radiation

Pie

Stephen`s Law:
P = (Sigma) · A · e · T^4
P in = P out
e = 1 for blacktop;
1150 W = (Sigma) · T^4
(Sigma) = 5.669 · 10 ^(-8) W/m²K^4
T^4 = 1150 : ( 5.669 · 10^(-8) )
T^4 = 202.875 · 10^8
$T = \sqrt[4]{202.857 * 10 ^{8} }$
T = 3.774 · 10² = 377.4 K
Answer: Equilibrium temperature is 377.4 K.

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3 years ago

Determine the momentum of a 15,000 kg truck traveling at 15 m/s

S_A_V [24]

Answer:

mass*velocity=1.5*10^4 * 15

= 22.5*10^4

6 0

3 years ago

The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate

ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

$\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}$ ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

$\theta=\frac{3.7m}{0.162m}=22.83rad$

$22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}$

to calculate the angular speed w we can use $\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}$

Thus, wf=12.68rad/s

C) We can use our result in B)

$\alpha=3.52\frac{rad}{s^2}$

I hope this is useful for you

regards

3 0

3 years ago

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