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2 years ago

Which of these experiments would make use of quantitative data?

Physics

2 answers:

jeka942 years ago

4 0

Answer:

A study of the different amounts of time it takes water to evaporate completely

Rasek [7]2 years ago

3 0

Answer:

The first one because quantitative is number

Explanation:

Hopefully it right

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Question No 1 Find the voltage drop across 24 ohm resistor and current flowing through 22 ohm resistor in the given circuit as s

lord [1]

Answer:

8.25 V

Explanation:

We can ignore the 22Ω and 122Ω resistors at the bottom. Since there's a short across those bottom nodes, any current will go through the short, and none through those two resistors.

The 2Ω resistor and the 44Ω resistor are in parallel. The equivalent resistance is:

1 / (1 / (2Ω) + 1 / (44Ω)) = 1.913Ω

This resistance is in series with the 12Ω resistor. The equivalent resistance is:

1.913Ω + 12Ω = 13.913Ω

This resistance is in parallel with the 24Ω resistor. The equivalent resistance is:

1 / (1 / (13.913Ω) + 1 / (24Ω)) = 8.807Ω

Finally, this resistance is in series with the 4Ω resistor. The equivalent resistance of the circuit is:

8.807Ω + 4Ω = 12.807Ω

The current through the battery is:

12 V / 12.807Ω = 0.937 A

The voltage drop across the 4Ω resistor is:

(0.937 A) (4Ω) = 3.75 V

So the voltage between the bottom nodes and the top nodes is:

12 V − 3.75 V = 8.25 V

4 0

3 years ago

A wire carries 3.7 A of current. A second wire is placed parallel to the first 8.0 cm away. What is the current flowing through

IgorC [24]

Answer:

The current in second wire is 5.0 A.

(B) is correct option.

Explanation:

Given that,

Current in first wire = 3.7 A

Distance = 8.0 cm

We need to calculate the magnetic field due to the current carrying wire

Using formula of magnetic field

$B=\dfrac{\mu_{0}I}{2\pi r}$

Where, I = current

r = distance

Put the value into the formula

For first wire

$B = \dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}$ ...(I)

For second wire,

The distance is 8-3.7 = 4.3 cm

$B' = \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}$ ...(II)

The magnetic field in both the wires,

From equation (I) and (II)

$\dfrac{\mu_{0}\times3.7}{2\pi \times3.4\times10^{-2}}= \dfrac{\mu_{0}\times I'}{2\pi \times(8-3.4)\times10^{-2}}$

$I'=\dfrac{3.7\times4.3\times10^{-2}}{3.4\times10^{-2}}$

$I'=4.68\ A\ approx = 5.0\ A$

Hence, The current in second wire is 5.0 A.

8 0

3 years ago

. Suppose that the displacement of an object is related to time according to the expression: x(t) = B t3 . Using dimensional ana

-Dominant- [34]

Answer:

The dimensionality of B is length per cubic time.

Explanation:

Units for displacement and time are length $[L]$ and time $[T]$ , respectively. Then, formula can be tested for dimensional analysis as follows:

$[L] = B\cdot [T]^{3}$

Now, let is clear $B$ to determine its units:

$B = \frac{[L]}{[T]^{3}}$

The dimensionality of B is length per cubic time.

6 0

2 years ago

Why just indirect evidence be used to study the structure of atoms?

ArbitrLikvidat [17]

It has to be used because you can not visually see them

6 0

2 years ago

A roller coaster is at the top of a hill and rolls to the top of a lower hill if mechanical energy is constant then on the top o

mafiozo [28]

The kinetic energy is greater on the second hill

hope i helped have a great day

4 0

3 years ago