Density will be mass/volume= 0.2/500 = 0.0004
We can use the heat equation,
Q = mcΔT
where Q is the amount of energy transferred (J), m is the mass of the substance (kg), c is the specific heat (J g⁻¹ °C⁻¹) and ΔT is the temperature difference (°C).
Q = 11.2 kJ = 11200 J
m = <span>145 g
</span>c = ?
ΔT = (67 - 22) °C = 45 °C
By applying the formula,
11200 J = 145 g x c x 45 °C
c = 1.72 J g⁻¹ °C⁻¹
Hence, specific heat of benzene is 1.72 J g⁻¹ °C⁻¹.
Answer: 67 mmHg
Explanation:
According to Dalton's Gas Law, the total pressure of a mixture of gases is the sum of the pressure of each individual gas.
i.e Ptotal = P1 + P2 + P3 + .......
In this case,
Ptotal = 512 mmHg
P(oxygen) = 332 mmHg
P(carbon mono-oxide) = 113 mmHg
Remaining pressure (P3) = ?
To get P3, apply Dalton's Gas Law formula
Ptotal = P(oxygen) + P(carbon mono-oxide) + P3
512 mmHg = 332 mmHg + 113 mmHg + P3
512 mmHg = 445 mmHg + P3
P3 = 512 mmHg - 445 mmHg
P3 = 67 mmHg
Thus, the remaining pressure is 67 mmHg
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