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3 years ago

Why is it important to waft when smelling chemicals?

Chemistry

2 answers:

Katena32 [7]3 years ago

6 0

The answer is C, <span>Many chemicals are dangerous </span>

Angelina_Jolie [31]3 years ago

4 0

Answer:

C. Many chemical are dangerous is the correct answer

Explanation:

It is important to waft when smelling chemicals because Many chemical are dangerous.

wafting chemicals is very important because chemicals are very dangerous they can cause damage to the mucous membrane and throat.

While working in the laboratory if we use a direct sniff of a chemicals the smell of the chemicals causes nausea and also a headache its odor can be very toxic that can harm human health.

Thus this is the reason wafting is important when smelling chemicals.

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The conjugate acid of ch3nh2 is ________. the conjugate acid of ch3nh2 is ________. ch3nh2+ ch3nh2 ch3nh3+ ch3nh+ none of the ab

Verizon [17]

The conjugate acid of ch3nh2 is ch3nh3+<span>.
</span>For example methylamine in water chemical reaction:
CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻(aq).
According to Bronsted-Lowry theory acid are donor of protons and bases are acceptors of protons (the hydrogen cation or H⁺). Methylamine (CH₃NH₂) is Bronsted base and it can accept proton and become conjugate acid (CH₃NH₃⁺).

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3 years ago

The concentration of Pb²⁺ in a sample of wastewater is to be determined by using gravimetric analysis. To a 100.0-mL sample of t

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Answer:

0.005404 M

Explanation:

$Pb^{2+}(aq) + Na_{2}CO_{3}(aq) ---> PbCO_{3}(s) + 2Na^{+}(aq)$

Since you added an excess of sodium carbonate you warrantied that all the $Pb^{+2}$ in the sample reacted with it. So we can say that the insoluble lead (II) carbonate $PbCO_{3}$ contains all the $Pb^{+2}$ ions in the original sample.

The moles of $PbCO_{3}$ are:

$moles-of-PbCO_{3}=\frac{mass-of-PbCO_{3}}{Molecular-weight-of- PbCO_{3}}=\frac{0.1443g}{267\frac{g}{mol}}=0.00054 mol$

One mol of $Pb^{+2}$ is required to form one mol of $PbCO_{3}$ . So, the stoichiometric relationship between them is 1:1.

$Pb^{+2} +CO_{3}^{-2} - - - > PbCO_{3}$

Knowing this, 0.00054 is also the number of moles of $Pb^{+2}$ in the original sample.

So, the concentration of $Pb^{+2}$ in the original sample is:

$M = \frac{mol-of-Pb^{+2}}{volume-wastewater-(liters)}=\frac{0.00054}{0.1L}=0.005404 M$

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4 years ago

Which part of the microscope should never be used under high power?

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3 years ago

An unknown element is a mixture of

seropon [69]

Answer:

10.13086%

Explanation:

129y + 132(1-y) = 129.91

129y + 132 - 132y = 129.91

-3y = -2.09

y = 0.69666 (5 s.f.)

% abundance of 132X = 100% - (129×0.69666)%

= 100% - 89.86914%

= 10.13086%

= 10.1% (3 significant figures)

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3 years ago

Given you have 1.93 mols of NaCl, find the molarity of a 2.5 L solution

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Answer:

0.77 M

Explanation:

Molarity is the concentration of a solution per liter

C= concentration

n= number of moles

V= volume of solution

The formula we will use is C= n/V

C= n/V

C= (1.93 mol NaCl)/(2.5 L of solution)

C= 0.772 mol/L

Since this concentration is given in moles per liters of a solution, this concentration is also the molarity.

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*Include two significant digits in final answer*

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3 years ago