A chemist measures the solubility of lead(ii) bromide in water to be 2. 96 g/l. calculate the ksp value for the solid. the ksp v
1 answer:
The solubility product, ksp of PbBr₂ is 2.102 × 10⁻⁶
<h3>What is solubility?</h3>The solubility of a solute is defined as the maximum amount of that solute that can be dissolved in a known quantity of solvent at a given temperature.
<h3>What is a solubility product? </h3>Some salts are sparingly soluble in a solvent. For them, we calculate the solubility product.
It is an equilibrium constant that defines the relationship between a solid and its respective ions in an aqueous solution in equilibrium.
The greater the solubility product, the greater the solubility and vice versa.
Here, the solubility of PbBr₂ = 2.96 g/l
Molar solubility of PbBr₂ = = 2.96/367 = 8.07 × 10⁻³
At equilibrium,
1 mole of PbBr2 dissociates into 1 mole of Pb²⁺ ions and 2 moles of Br⁻
Let the molar concentration of Pb²⁺ be x, then the molar concentration of Br⁻ is 2x
Ksp = x.(2x)²
= 4x³
Substitute, x = 8.07 × 10⁻³
Ksp = 4 (8.07 × 10⁻³)³
= 2.102 × 10⁻⁶
Thus, The ksp of PbBr₂ is 2.102 × 10⁻⁶
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Answer:
Se detailed explanation.
Explanation:
Hello,
In this case, since both magnesium and calcium ions are in group IIA, we can review the following similar properties:
- Since both calcium and magnesium are in group IIA they have two valence electrons, it means that the both of them have two electrons at their outer shells.
- They are highly soluble in water when forming ionic bonds with nonmetals such as those belonging to halogens and oxygen's family.
- Calcium has 18 electrons and magnesium 10 which are two less than the total protons (20 and 12 respectively) since the both of them have lost two electrons due their ionized form.
- Their electron configurations are:
It means that the both of them are at the region since it is the last subshell at which their electrons are.
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