Answer:
n = 756.25 giga electrons
Explanation:
It is given that,
If the charge on the negative plate of the capacitor,
Let n is the number of excess electrons are on that plate. Using the quantization of charges, the total charge on the negative plate is given by :
e is the charge on electron
or
n = 756.25 giga electrons
So, there are 756.25 giga electrons are on the plate. Hence, this is the required solution.
Answer:
<em><u>two childrens are sitting on a see saw but can't swing.it means both weight is same (a=b) </u></em>
Explanation:
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Answer:
1.439 × 10¹¹ m is the answer.
Explanation:
1 light-second = 2.998 × 10⁸m
480 light-seconds = 480 × 2.998 × 10⁸
= 1439.04 × 10⁸
= 1.439 × 10¹¹
∴ 1.439 × 10¹¹ m is the answer.
The potential difference does work on the electron. The work is given by:
W = Vq
W = work, V = potential difference, q = electron charge
Given values:
V = 6V, q = 1.6x10^-19C
Plug in and solve for W:
W = 6(1.6x10^-19)
W = 0.96aJ
The amount of matter in an object is called its, mass. How much the mass weights would be referred to as weight