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lilavasa [31]
3 years ago
6

What is the distance from the center of the Moon to the point between Earth and the Moon where the gravitational pulls of Earth

and Moon are equal? The mass of Earth is 5.97 × 1024 kg, the mass of the Moon is 7.35 × 1022 kg, the center-to-center distance between Earth and the Moon is 3.84 × 108 m, and G = 6.67 × 10-11 N ∙ m2/kg2.
Physics
1 answer:
Tanya [424]3 years ago
5 0

Answer:

r = 3.84 \times 10^7 m

Explanation:

Let say the distance at which gravitational force due to both Earth and moon is zero is given by force force balance

so it is given as

F_{moon} = F_{Earth}

\frac{GM_{moon}}{r^2} = \frac{GM_{earth}}{(d - r)^2}

so we have

\frac{M_{moon}}{r^2} = \frac{M_{earth}}{(d - r)^2}

\frac{7.35 \times 10^{22}}{r^2} = \frac{5.97 \times 10^{24}}{(3.84 \times 10^8 - r)^2}

now we have

\frac{2.71}{r} = \frac{24.4}{3.84\times 10^8 - r}

10.4 \times 10^8 - 2.71 r = 24.4 r

now we have

r = 3.84 \times 10^7 m

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With the addition of vectors we can find that the correct answer is:

   C)   Q> P > R =  S > T

The addition of vectors must be done taking into account that they have modulus and direction. The analytical method is one of the easiest methods, the method to do it is:

  • Set a Cartesian coordinate system
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In this exercise indicate that the modulus of all vectors is the same, suppose that the value of the modulus is A.

We fix a Cartesian coordinate system with the horizontal x axis and the vertical y axis, we can see that we do not need to perform any decomposition, so we perform the algebraic sums

Diagram P

x-axis

         x = 2A

y-axis  

         y = 2A

The modulus of the resulting vector can be found with the Pythagorean Theorem

          P = \sqrt{x^2+y^2}

          P = \sqrt{4A^2 +4A^2 }= \sqrt{8}  \  A

          P = 2 √2  A

         

Diagram Q

x-axis

        x = 3A

y-axis  

        y = A

Resulting

       Q = \sqrt{x^2+y^2}

       Q =\sqrt{9A^2 + A^2 }  

       Q = \sqrt{10} \ A

       

Diagram R

x- axis

       x = 0

y-axis

        y = 2 A

Resulting

       R =\sqrt{4A^2 + 0}  

       R = \sqrt{4} \ A

Diagram S

x-axis

       x = 2 A

y-axis

        y = 0

 

Resulting

       S = 2A

Diagram T

x- axis

      x = 0

y-axis  

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Resultant T = 0

We order the diagram from highest to lowest

    Q> P> R = S> T

When reviewing the different answers, the correct one is:

   C.  Q> P> R = S> T

Learn more about adding vectors here:

brainly.com/question/14748235

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