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o-na [289]
3 years ago
8

Choose the thermochemical equation that illustrates ΔH°f for Li2SO4. Choose the thermochemical equation that illustrates ΔH°f fo

r Li2SO4. 8 Li2SO4(s) → 16 Li(s) + S8(s, rhombic) + 16 O2(g) Li2SO4(aq) → 2 Li+(aq) + SO42-(aq) 2 Li+(aq) + SO42-(aq) → Li2SO4(aq) 16 Li(s) + S8(s, rhombic) + 16 O2(g) → 8 Li2SO4(s) 2 Li(s) + 1/8 S8(s, rhombic) + 2 O2(g) → Li2SO4(s)
Chemistry
1 answer:
Deffense [45]3 years ago
8 0

Answer:

2Li(s) + ⅛S₈(s, rhombic) + 2O₂(g) → Li₂SO₄(s)  

Explanation:

A thermochemical equation must show the formation of 1 mol of a substance from its elements in their most stable state,.

The only equation that meets those conditions is the last one.

A and B are wrong , because they show Li₂SO₄ as a reactant, not a product.

C is wrong because Li⁺ and SO₄²⁻ are not elements.

D is wrong because it shows the formation of 8 mol of Li₂SO₄.

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Anika [276]

Answer:

The answer A is correct

Explanation:

lazy, fast, rapid

4 0
4 years ago
In your reaction you started with a solution that was approximately 8 M acetic acid and 4 M isopentyl alcohol. Use the equilibri
V125BC [204]

The final concentrations of water, isopentyl acetate, isopentyl alcohol, and acetic acid obtained on using equilibrium expression are 3.4M, 3.4M, 0.6M , 4.6M

Using ICE table:-

      Acetic acid  +  Isopentyl alcohol   ------>    Isopentyl acetate +  water

I         8M                   4M                                           0                           0

C        8-x                   4-x                                          +x                          +x                      

E        8-x                   4-x                                          +x                          +x

Equilibrium constant (Keq) = 4.2

On using the equilibrium expression -

Keq = [Product] / [Reactant]

Keq = x^2 / (8-x) (4-x )

4.2  =  x^2 / 32 - 8x - 4x + x^2

    x =  3.4

Concentration of acetic acid  = 8-x = 8-3.4 = 4.6M

Concentration of isopentyl alcohol = 4-x = 4-3.4 = 0.6M

Concentration of isopentyl acetate = x = 3.4M

Concentration of water = x = 3.4M

Learn more about equilibrium expression

brainly.com/question/14751091

#SPJ4

4 0
2 years ago
What is the diffrence between kinetic and potential energy
Aneli [31]
Potential Energy is the stored energy in an object or system because of its position or configuration. Kinetic energy of an object is relative to other moving and stationary objects in its immediate environment.
4 0
3 years ago
I need help with this ASAP PLEASE
Artemon [7]

439.3 g CO2

Explanation:

First find the # of moles of CO2 that results from the combustion of 3.327 mol C3H6:

3.227 mol C3H6 × (6 mol CO2/2 mol C3H6)

= 9.981 mol CO2

Use the molar mass of CO2 to determine the # of grams of CO2:

9.981 mol CO2 x (44.01 g CO2/1 mol CO2)

= 439.3 g CO2

5 0
3 years ago
how many moles of oxygen are needed to burn 1.33 moles of methyl alcohol (ch3oh)?2ch3oh 3o2 2co2 4h2o
dlinn [17]
<span>2 CH3OH + 3 O2 = 2 CO2 + 4 H2O

2 moles CH3OH ---------------- 3 moles O2
1.33 moles CH3OH ----------- ( moles O2)

moles O2 = 1.33 x 3 / 2

moles O2 = 3.99 / 2

= 1.995 moles of O2</span>
3 0
3 years ago
Read 2 more answers
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