Tap water used for drinking is considered in the DIL calculations; true
Answer:
- <u>Alkaline or basic solution </u>(alkaline and basic means the same)
Explanation:
According to the <em>pH</em>, solutions may be classified as neutral, acidic, or alkaline (basic).
This table shows such classification:
pH classification
7 neutral
> 7 alkaline or basic
< 7 acidic
Thus, since the pH of the solution is 8.3, which is greater than 7, the solution is classified as basic (alkaline).
Additionally, you must learn that pH is a logarithmic scale for the concentration of hydronium ions in the solution.
You can calculate the concentration of hydronium ions using antilogarithm properties:
![pH=-log[H_3O^+]\\ \\ {[H_3O^+]}=10^{-pH}\\ \\ {[H_3O^+]}=10^{-8.3}=0.00000000501](https://tex.z-dn.net/?f=pH%3D-log%5BH_3O%5E%2B%5D%5C%5C%20%5C%5C%20%7B%5BH_3O%5E%2B%5D%7D%3D10%5E%7B-pH%7D%5C%5C%20%5C%5C%20%7B%5BH_3O%5E%2B%5D%7D%3D10%5E%7B-8.3%7D%3D0.00000000501)
NaOH solutions are alkaline solutions, bases, according to Arrhenius model, because they contain OH⁻ ions and release them when ionize in water.
Okay
40ml-35ml=5ml
5ml is the volume of the rock
1ml=1cm3
hence the volume of the rock is 5cm3
Answer:
Explanation:
A pink rose- in codominance
Genes IA, IN, and IB.- Multiple alleles
Equal proportions- incomplete dominance
The mass of Ce(NO3)₄ that will be needed to create the solution was 24.16 g (in grams).
<h3>
What exactly is the solution?</h3>
A homogenous mixture with one or even more solutes that have been dissolved in the solvent is known as a solution. The material that a solute dissolves in to create a homogenous mixture is known as a solvent. To create a homogenous mixture, a component must dissolve in a solvent.
<h3>
What is an illustration of a solution?</h3>
One nanometer or smaller particles are referred to as a solution in a homogeneous mixture made up of two or more components. There are many different types of solutions, including sugar and salt solutions and fizzy water. Each component shows up as a different phase in a solution.
<h3>
Briefing:</h3>
Mole of Ce(NO₃)₄ = 0.06225 mole
Molar of Ce(NO₃)₄ = 140.12 + 4[14 + (16×3)]
= 140.12 + 4[14 + 48]
= 140.12 + 4[62]
= 140.12 + 248
= 388.12 g/mol
Mass of Ce(NO₃)₄ = 0.06225 × 388.12
Mass of Ce(NO₃)₄ = 24.16 g
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