There are several reasons why the skeletal system is unique. here are a few of the reasons:
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Given: The systolic arterial blood pressure observed for 20 dogs is normally distributed with a mean of 152 mm of mercury (Hg) and a standard deviation of 18 mm of Hg.
To find: P(100 < 152)
Method: Calculation of Z-Score followed by the probability or area of the bell curve at X = 100.
Solution:
Mean u = 152, std s = 18
Z score =
The value of P(100<152) is calculated by looking at the value of Z in the Z score for the standard normal distribution given in the image.
P(Z=-2.89) = 0.0019
The P(Z = -2.89) corresponds to the area in the left tail of the bell curve.
Thus the probability of 100 mm Hg blood pressure is 0.0019.
The parent's genotypes are 
and 
respectively. When crossed together, all possible genotypes can be expressed. 1/4 AB blood, 1/4 A blood (heterozygous), 1/4 B blood (heterozygous) and 1/4 O blood. A Punnett square has been uploaded to support this.
