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3 years ago

Tell me what you think in galaxies do aliens exist tell me why and your view

Chemistry

1 answer:

mart [117]3 years ago

4 0

Answer:

I do not know. I think there is .as we are the living creatures in this earth. maybe aliens are creatures of other planet or galaxies. I am not scientists to prove it.sorry.

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Why are protons in an atom so important? Question 5 options: A. Protons determine the atoms' identity (type of element) and wher

Gennadij [26K]

Your answer is A my friend as the atomic number of an atom is determined by the number of protons

4 0

3 years ago

Read 2 more answers

A container has a volume of 2.79 L and a pressure of 5.97 atm. If the pressure changes to 1460 mm Hg, what is the container’s ne

maw [93]

Answer:

8.68 L is the new volume

Explanation:

You use Boyle's law for this.

$P_{1}V_{1}=P_{2}V_{2}$

$P_{1}$ = first pressure

$P_{2}$ = second pressure

$V_{1}$ = first volume

$V_{2}$ = second volume

Convert pressure from atm to mmHg (use same units):

5.97 x 760 = 4537.2 -> 4.54 x 10³

...maintain 3 significant figures in calculation, and round as needed...

(4.54 x 10³ mmHg)(2.79 L) = (1460 mmHg)( $V_{2}$ )

(4.54 x 10³ mmHg)(2.79 L) / (1460 mmHg) = $V_{2}$ = 8.68 L

Hope this helps :)

5 0

3 years ago

What is the electron configuration of Iron

Novay_Z [31]

The electron configuration of Iron is:

[Ar] 3d⁶4s²

5 0

3 years ago

Which medium slows the speed of light waves? Select all that apply.

77julia77 [94]

Answer : pool water

Explanation:

3 0

3 years ago

Calculate the freezing point of a solution made from 220g of octane (C Hua), molar mass = 114,0 gmol dissolved in 1480 g of benz

stiv31 [10]

Answer: Freezing point of a solution will be $-1.16^0C$

Explanation:

Depression in freezing point is given by:

$\Delta T_f=i\times K_f\times m$

$\Delta T_f=T_f^0-T_f=(5.50-T_f)^0C$ = Depression in freezing point

i= vant hoff factor = 1 (for non electrolyte)

$K_f$ = freezing point constant = $5.12^0C/m$

m= molality

$\Delta T_f=i\times K_f\times \frac{\text{mass of solute}}{\text{molar mass of solute}\times \text{weight of solvent in kg}}$

Weight of solvent (benzene)= 1480 g =1.48 kg

Molar mass of solute (octane) = 114.0 g/mol

Mass of solute (octane) = 220 g

$(5.50-T_f)^0C=1\times 5.12\times \frac{220g}{114.0 g/mol\times 1.48kg}$

$(5.50-T_f)^0C=6.68$

$T_f=-1.16^0C$

Thus the freezing point of a solution will be $-1.16^0C$

3 0

3 years ago