The answer should be B - Nitrogen Dioxide.
Answer:
4.13 moles of Fe
Explanation:
Step 1: Write the balanced equation
3 CO + Fe₂O₃ ⇒ 2 Fe + 3 CO₂
Step 2: Establish the appropriate molar ratio
According to the balanced equation, the molar ratio of CO to Fe is 3:2.
Step 3: Calculate the moles of Fe formed from 6.20 moles of CO
We will use the previously established molar ratio.
6.20 mol CO × 2 mol Fe/3 mol CO = 4.13 mol Fe
Enthalpy of formation is calculated by subtracting the total enthalpy of formation of the reactants from those of the products. This is called the HESS' LAW.
ΔHrxn = ΔH(products) - ΔH(reactants)
Since the enthalpies are not listed in this item, from reliable sources, the obtained enthalpies of formation are written below.
ΔH(C2H5OH) = -276 kJ/mol
ΔH(O2) = 0 (because O2 is a pure substance)
ΔH(CO2) = -393.5 kJ/mol
ΔH(H2O) = -285.5 kJ/mol
Using the equation above,
ΔHrxn = (2)(-393.5 kJ/mol) + (3)(-285.5 kJ/mol) - (-276 kJ/mol)
ΔHrxn = -1367.5 kJ/mol
<em>Answer: -1367.5 kJ/mol</em>
