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lisov135 [29]
3 years ago
7

An athlete kicks a soccer ball that starts at rest so that it leaves their foot with a speed of 10m/s from the top o f a rectang

ular shaped canyon. If the athlete's foot is in contact with the ball for only 0.02 seconds, determine the accceleration of the ball during the kick.
Physics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

a=500m/s^2

Explanation:

We need only to apply the definition of acceleration, which is:

a=\frac{v_f-v_i}{t_f-t_i}

In our case the final velocity is v_f=10m/s, the initial velocity is v_i=0m/s since it departs from rest, the final time is t_f=0.02s and the initial time we are considering is t_i=0s

So for our values we have:

a=\frac{10m/s-0m/s}{0.02s-0s}=500m/s^2

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Answer:

No

Explanation:

Unless there are other external forces, this will never be true. Because according to energy conservation, potential energy will be converted to kinetic energy as the ball falls down (so it loses height and gain speed). And vice versa, kinetic to potential when it bounces back. So the potential energy after must be the same (or smaller if losing heat to external environment), so it can only get the the same height or less, but not more.

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Answer:

(a) 3.13 m/s

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Explanation:

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Let v be the velocity of ball as it hit the ground.

(a) h = 0.5 m

Use third equation of motion.

v^2 = u^2 + 2 g h

v^2 = 0 + 2 x 9.8 x 0.5

v^2 = 9.8

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(b) h = 5 m

Use third equation of motion.

v^2 = u^2 + 2 g h

v^2 = 0 + 2 x 9.8 x 5

v^2 = 98

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(c) h = 10 feet = 3.048 m

Use third equation of motion.

v^2 = u^2 + 2 g h

v^2 = 0 + 2 x 9.8 x 3.048

v^2 = 59.74

v = 7.73 m/s

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3 years ago
Will Give Brainliest and 25 Points
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As the car gets the closer the sound waves get closer, so the horn becomes louder.

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Explanation:

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tensa zangetsu [6.8K]

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Explanation:

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2 years ago
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