<u>Answer</u>:
By tracking oxidation numbers we can identify the number electron in the atom
<u>Explanation</u>:
Tracking of electrons helps us to know when and how many electrons get transferred from one atom to other atom . Oxidation referred as the “loss of one or more electrons” by an atom. When the oxidation number of an element increases, there is a loss of electrons and that element is being oxidized. Oxidation numbers are usually written with the sign (+plus or −minus) followed by the magnitude, which is the opposite of charges on ions. In their elemental stage oxidation number of an atom is zero.
Answer:
The correct option is;
C. Old Age River
Explanation:
Among the three stages of the development of a river, which are the youthful, mature, and old age stages, the old age river is least dynamic
The water is very slow moving with a low gradient and lesser erosive power to alter the landscape which results in the appearance of flood planes
Examples of old age rivers include, lower Ganges, lower Nile, Indus, and Yellow rivers
Old age rivers are characterized by a broad shape, with a wide flood plane, a very gentle gradient and the water current is low.
<span>Grams of solute per 100 grams of water</span>
Explanation:
It is given that the total volume is (10 mL + 60 mL) = 70 mL.
Also, it is known that
= 
Where,
= total volume
= initial volume
Therefore, new concentration of
= 
= 
= 0.43 M
New concentration of NaOH = 
= 
= 0.14 M
So, the given reaction will be as follows.

Initial: 0.43 0.14 0
Change: -0.14 -0.14 0.14
Equilibrium: 0.29 0 0.14
As it is known that value of
= 4.74
Therefore, according to Henderson-Hasselbalch equation calculate the pH as follows.
pH = ![pK_{a} + log \frac{[CH_{3}COO^{-}]}{[CH_{3}COOH]}](https://tex.z-dn.net/?f=pK_%7Ba%7D%20%2B%20log%20%5Cfrac%7B%5BCH_%7B3%7DCOO%5E%7B-%7D%5D%7D%7B%5BCH_%7B3%7DCOOH%5D%7D)
= 
= 4.74 + (-0.316)
= 4.42
Therefore, we can conclude that the pH of given reaction is 4.42.
Answer:
ClO₄⁻
Explanation:
When an ion is hydrated it is surrounded by water molecules, thus, as small is the ion, more molecules may surround it, and it will be more strongly hydrated. In this case, the Cl is small than the S atom, because Cl is from group 17, and S from group 16, and Cl has more valence electrons, which will be more attracted to the nuclei.
So, ClO₄⁻ will be more strongly hydrated.