Collection of data
mass(m) =5,96 (given)
Molarmass(M) =1(39)+1(16)+1(1)=56 (we use the periodic table to calculate the molar mass of KOH)
Moles(n) =?? (It is wat we have to calculate)
We can use the formula n=m/M
Therefore n=5,96/56=0,10643moles
C. 50% Unless the question is saying he only gets heads once, in which case it would be 0%. Or the coin could have 2 heads. Then it would be 100%. But I'm pretty sure it's 50%.
