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3 years ago

Acid+base->salt+waterWhat type of reaction is this?

Chemistry

2 answers:

Lelechka [254]3 years ago

5 0

Answer:

The reaction of an acid with a base is called a neutralization reaction. The products of this reaction are a salt and water.

timurjin [86]3 years ago

4 0

Answer:

Neutralization reaction

Explanation:

Neutralization reaction it the reaction of acids and bases that form salt and water

hope it's helpful ❤❤❤❤

THANK YOU.

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Which water usage uses the least amount of water in a year in the United States

statuscvo [17]

Answer: a

Explanation:

Industry uses only about 18% while the others use around 70-90% of water.

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2 years ago

A solution of 1.50 g of solute dissolved in 25.0 mL of H₂O at 25°C has a boiling point of 100.45°C. (d) Find the van’t Hoff fact

givi [52]

The van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

<h3>What is the value of van 't Hoff factor?</h3>

For most non-electrolytes dissolved in water, the Van 't Hoff factor is essentially $ 1 $ . For most ionic compounds dissolved in water, the Van 't Hoff factor is equal to the number of discrete ions in a formula unit of the substance.

Which has highest Van t Hoff factor?

The Van't Hoff factor will be highest for

A. Sodium chloride.

B. Magnesium chloride.

C. Sodium phosphate.

D. Urea.

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1 year ago

What is the nucleus of an atom split

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3 years ago

Read 2 more answers

In solid NaCl, the equilibrium separation between neighboring Na+ and Cl- ions is 0.283 nm. Calculate the coulombic energy betwe

const2013 [10]

Explanation:

It is given that r = 0.283 nm. As 1 nm = $10^{-9} m$ .

Hence, 0.283 nm = $0.283 \times 10^{-9} m$

Formula for coulombic energy is as follows.

$U_{coulomb} = -1.748 \frac{e^{2}}{4 \pi \epsilon_{o} r}$

where, e = $1.6 \times 10^{-19}$ C

$\epsilon_{o}$ = $8.85 \times 10^{-12}$

$U_{coulomb} = -1.748 \frac{(1.6 \times 10^{-19}^{2}}{4 \times 3.14 \times 8.85 \times 10^{-12} \times 0.283 \times 10^{-9}}$

= $1.423 \times 10^{-18} J$

As 1 eV = $1.6 \times 10^{-19} J$

So, 1 J = $\frac{1 eV}{1.6 \times 10^{-19}}$

Hence, U = $\frac{1.423 \times 10^{-18} J}{1.6 \times 10^{-19} J}$

= 8.9 eV

Also, 1 J = $\frac{10^{-3} kJ}{6.022 \times 10^{23}mol}$

= $1.67 \times 10^{-27}$ kJ/mol

Therefore, U = $1.423 \times 10^{-18} J \times 1.67 \times 10^{-27}$ kJ/mol

= $2.37 \times 10^{-45} kJ/mol$

7 0

3 years ago

Please anyone answer this question

Ainat [17]

Answer:

A, 18.4 and 34!

Explanation:

The Burette seems to have ~18.4 of the liquid? substance in it, and the Measuring Cylinder seems to have ~34 of the liquid? substance in it. So, it is A! :]

Hope this helps!!

7 0

3 years ago

Acid+base->salt+waterWhat type of reaction is this?​

Acid+base->salt+waterWhat type of reaction is this?