It will sink cause it is a rock
Answer:
What happens to the wavelength when you increase the rate of vibration (how fast your hand moved back and forth). After increasing the rate of vibration, the wavelength decreased.\
Answer:
The limiting reagent is the SF₄
Explanation:
In order to determine the limiting reagent we convert the mass of the reactants to moles, and then, we work with stoichiometry.
4.687 g / 108.06 g/mol = 0.0433 moles of SF₄
6.281 g / 333.8 g/mol = 0.0188 moles of I₂O₅
The reaction is: 5SF₄ + 2I₂O₅ = 4IF₅ + 5SO₂
Ratio is 5:2. 5 moles of fluoride react with 2 moles of pentoxide
Then, 0.0433 moles of fluoride will react with (0.0433 . 2) / 5 = 0.0173 moles
We have 0.0188 moles of I₂O₅ and we need 0.0173 so there are some moles of pentoxide that remains after the reaction. In conclussion, the limiting reagent is the SF₄. We verify:
2 moles of pentoxide react with 5 moles of SF₄
Therefore, 0.0188 moles of I₂O₅ will react with (0.0188 . 5) / 2 = 0.0470 moles.
As we have 0.0433 moles of SF₄, we do not have enough moles.
To find the amount of moles in 0.00032g of lithium, all you have to do is apply the formula n (moles) = m (mass, grams)/MM(molar mass). Molar mass is the atomic weight of the substance, and all you have to do is look at the periodic table. Lithium's is 6.94.
So, n (lithium) = 0.00032/6.94
n (lithium) = 0.000046 moles (2 d.p)
Take into account the number of atoms in the molecule for other calculations. Some elements are diatomic, which means they occur as two atoms of the same element bonded, such as hydrogen (H2) and chloride (Cl2). This means that to find moles of a substance such as Cl2, you need to multiply the molar mass by 2, since there are 2 atoms. Additionally, for compounds, you need to find the sum of all the elements involved's molar mass. For example, when you’re trying to find the moles in table salt, NaCl (sodium chloride), add the atomic weight of sodium and chlorine together for your molar mass.
Hope this helped!
True:
The result is two genetically identical daughter nuclei.