Answer: 1.4 seconds
<u>Step-by-step explanation:</u>
The equation is: h(t) = at² + v₀t + h₀ where
- a is the acceleration (in this case it is gravity)
- v₀ is the initial velocity
- h₀ is the initial height
Given:
- a = -9.81 (if it wasn't given in your textbook, you can look it up)
- v₀ = 12
- h₀ = 3
Since we are trying to find out when it lands on the ground, h(t) = 0
EQUATION: 0 = 9.81t² + 12t + 3
Use the quadratic equation to find the x-intercepts
a=-9.81, b=12, c=3
Note: Negative time (-0.2) is not valid
The question involves the concept & equations associated with projectile motion.
Given:
y₁ = 1130 ft
v₁ = +46 ft/s (note positive sign indicates upwards direction)
t = 6.0 s
g = acceleration due to gravity (assumed constant for simplicity) = -32.2 ft/s²
Of the possible equations of motion, the one we'll find useful is:
y₂ = y₁ + v₁t + 1/2gt²
We can just plug and chug to define the equation of motion:
<u><em>y = (1130 ft) + (46 ft/s)t + 1/2(-32.2 ft/s²)t²</em></u>
<em>(note: if you were to calculate y using t = 6.0 s, you'd find that y = 826.4 ft, instead of 830 ft exactly because of some rounding of g and/or the initial velocity)</em>
Answer:
Two lines are crossed by another line (called Transversal), the angles in matching corners are called corresponding angles. There are two parallel lines interest by the Transversal and ∠1 and ∠5 are made on the matching corners . Thus ∠1 and ∠5 are the corresponding angles .
Step-by-step explanation:
Answer:
9 3/8 ÷ 2 1/4
Step-by-step explanation:
too lazy too do it, plus if ur having a hard time doing fractions on a calc, just do 1÷4 as a replacement for .25 when shown 1/4. just go to frac calc in the future it makes it easy ro use....
Answer:
function= 2nd,6th
not a function=1st,3rd,4th,5th
Step-by-step explanation:
because in graphing a function, there should only be one y for the x. 2 or more y's in one x is considered as not a function
