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lord [1]
3 years ago
10

Which of the following is true? A. Lithium is the least reactive element in group 1, because it is the smallest and holds its va

lence electron more tightly than the others in the same group. B. Cesium is the most active group 1 metal, because its valence electron is held more tightly than the others in the same group. C. Group 1 elements are more reactive than the group 2 elements because they have more valence electrons to lose. D. The least reactive element in group 2 is the one with the largest atomic radium and the least amount of attraction between the nucleus
Chemistry
1 answer:
Dominik [7]3 years ago
6 0
I think the answer is c
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During the chemical reaction given below 21.71 grams of each reagent were allowed to react. Determine how many grams of the exce
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Answer: 16.32 g of O_2 as excess reagent are left.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} SO_2=\frac{21.71g}{64g/mol}=0.34mol

\text{Moles of} O_2=\frac{21.71g}{32g/mol}=0.68mol

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)  

According to stoichiometry :

2 moles of SO_2 require = 1 mole of O_2

Thus 0.34 moles of SO_2 will require=\frac{1}{2}\times 0.34=0.17moles  of O_2

Thus SO_2 is the limiting reagent as it limits the formation of product and O_2 is the excess reagent.

Moles of O_2 left = (0.68-0.17) mol = 0.51 mol

Mass of O_2=moles\times {\text {Molar mass}}=0.51moles\times 32g/mol=16.32g

Thus 16.32 g of O_2 as excess reagent are left.

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