Answer:
3) The relative concentrations of each gas must remain constant.
4)The concentration of each gas will not change.
Explanation:
- For the equilibrium system:
<em>X₂ + Y₂ ⇄ 2XY,</em>
The no. of moles of gases in each side is constant; there is 2 moles of gases at reactants side and 2 moles of gases at products side.
So, changing the volume will not affect on the equilibrium system.
<em>So, the right choice is:</em>
3) The relative concentrations of each gas must remain constant.
4)The concentration of each gas will not change.
Answer: During winter the Northern Hemisphere leans away from the sun, there are fewer daylight hours and the sun hits us at an angle. This makes it appear lower in the sky. In equatorial regions the length of days and the directness of sunlight don't change as much.
Hope this helps :)
We need to crack molecules in
order for us to get the desired molecule. For example, in the extraction of
crude oil, after entering the fractional distillation, it will give products
base on their molecular structure. The products are gasoline, diesel fuel, jet
fuel, wax, asbestos,kerosene.
Answer:
Yes, Pb3(PO4)2.
Explanation:
Hello there!
In this case, according to the given balanced chemical reaction, it is possible to use the attached solubility series, it is possible to see that NaNO3 is soluble for the Na^+ and NO3^- ions intercept but insoluble for the Pb^3+ and PO4^2- when intercepting these two. In such a way, we infer that such reaction forms a precipitate of Pb3(PO4)2, lead (II) phosphate.
Regards!
Answer: 
> 
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Explanation:
The order of boiling point depends upon the type of interactions present between the molecules.
Potassium fluoride (KF) is an ionic compound and the opposite ions are held together by strong electrostatic forces.
is a covalent compound and the molecules are held together by weak van der Waals' forces.
Formaldehyde is a polar compound due to presence of polar carbonyl group. Hence dipole-dipole force is present between formaldehyde molecules.
Thus the decreasing order of boiling point is:
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