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2 years ago

When burning 180g of glucose in the presence of 192g of oxygen, water and carbon dioxide are produced?

Chemistry

1 answer:

Aneli [31]2 years ago

3 0

The burning of glucose in presence of oxygen is called as combustion

The balanced reaction is

C6H12O6 + 6O2 ---> 6CO2 + 6H2O

Thus for each mole of glucose we need six moles of oxygen molecules

molar mass of glucose is 180g / mole

The moles of glucose present = mass / molar mass = 180 / 180 = 1 mole

The moles of oxygen present = mass / molar mass = 192 / 32 = 6 moles

Thus the reaction will go to completion and one mole of glucose will react with six moles of O2 to give six moles of CO2 and six moles of H2O

Mass of CO2 produced = moles X molar mass = 6 x 44 = 264 g

Mass of H2O produced = moles X molar mass = 6 x 18 = 108 g

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3 years ago

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2 years ago

What mass of silver chloride can be produced from 1.30 L of a 0.245 M solution of silver nitrate? The reaction described in Part

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Answer:

Explanation:

Given parameters:

Volume of AgNO₃ = 1.3L

Molarity or concentration AgNO₃ = 0.245M

Unknown:

Mass of AgCl produced = ?

Solution:

To solve this problem, we have to work from the known compound to the unknown one using the mole concept.

The known compound is the one that we can obtain the value of the number of moles from. Here it is the given AgNO₃ that can furnish us with this piece of information;

Now let us establish the balanced reaction equation;

2AgNO₃ + CaCl₂ → 2AgCl + Ca(NO₃)₂

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Find the number of moles of AgNO₃;

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= 1.3 x 0.245

= 0.32moles

From the balanced reaction equation;

2 mole of AgNO₃ produced 2 moles of AgCl

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2 years ago