The structure of the alkyl bromides used in a malonic ester synthesis of ethyl 2-methyl-4-pentenoate are as drawn in the attached image.
<h3>Ethyl 2-methyl-4-pentenoate by Malonic ester synthesis.</h3>
The malonic ester synthesis is a chemical reaction characterized by the alkylation of diethyl malonate or a similar ester of malonic acid at the carbon alpha (directly adjacent) to both carbonyl groups, and subsequently converted to a substituted acetic acid.
Hence, it follows from the structure of Ethyl 2-methyl-4-pentenoate that the alkyl bromides used are Ethyl bromide and methyl bromide.
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When water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.
<h3>What is hydrolysis reaction?</h3>
There are so many kinds of reaction in chemistry we know that a chemical reaction occurs between reactant molecules in order to yield products in the reactants.
The hydrolysis reaction is a breaking up reaction. In a hydrolysis reaction, water is used to break up a molecule. Hence in a hydrolysis reaction water could be regarded as one of the reactants in the reactions going on in the system.
We know that a hydrolysis is a reaction in which water reacts with another reactant molecule to yield products in the reaction. Thus, when water is added to a compound in a chemical equation, a new compound can be formed, it is called a hydrolysis reaction.
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Answer:
2Li(s) + 2H₂O(ℓ) ⟶ 2Li⁺(aq) + 2OH⁻(aq) + H₂(g)
Explanation:
An ionic equation uses the symbols (aq) [aqueous] to indicate molecules and ions that are soluble in water, (s) [solid] to indicate insoluble solids, and (ℓ) to indicate substances (usually water) in the liquid state.
In this reaction, solid lithium reacts with liquid water to form soluble lithium hydroxide and gaseous hydrogen
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1. Molecular equation
2Li(s) + 2H₂O(ℓ) ⟶ 2LiOH(aq) + H₂(g)
2. Ionic equation
Lithium hydroxide is a soluble ionic compound, so we write it as hydrated ions.
2Li(s) + 2H₂O(ℓ) ⟶ 2Li⁺(aq) + 2OH⁻(aq) + H₂(g)
<span>i think the answer should be 2KOH +H2SO4=K2SO4+2H20</span>
Hi!
Basically, you will want to cross product your 20 moles of HCl with the number of moles in your H2 (so 1), with that and the number of moles in the HCl (2), you will find that 10 moles of H2 will form from 20 moles of HCl