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kramer
3 years ago
12

What are the three components of the equation for the second law of motion?

Physics
1 answer:
noname [10]3 years ago
6 0

force= mass × acceleration

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A 250 watt electric bulb is lighted for 5 hours daily and four 6 watt bulbs are lighted for 4.5 hours daily. Calculate the energ
densk [106]

Answer:

38.024 KWh

Explanation

250 watts multiplied with 5 hours daily multiplied with 28 days monthly equals 35000 Watt hours. Divided by a 1000 to get the KWh equals 35 KWh.

= 250×5hrs× 28days

= 35000watts

= 35000/1000

= 35KWh

Four 6 watt lightbulbs equals 24 watts 4x6=24

Hence, 24×4.5hrs×30days

= 3024watts

= 3024/1000

= 3.024KWhr

The total amount of energy consumed in the month of February = 35 KWh + 3.024 KWh = 38.024 KWh

Note that I had to use 28days since we are considering the month of February.

5 0
3 years ago
In the far future, astronauts travel to the planet Saturn and land on Mimas, one of its 62 moons. Mimas is small compared with t
OverLord2011 [107]

Answer:

a) h = 13,205.4 m

b)  r_f = 2.12 106 m

c)        e% = 0.68%

Explanation:

a) This is an exercise we are asked to use energy conservation,

Starting point. On the surface of Mimas

        Em₀ = K = ½ m v²

Final point. Where the ball stops

       Em_{f} = U = m g h

        Em₀ = Em_{f}

        ½ m v² = m g h

         h = ½ v² / g

let's calculate

         h = ½ 41² / 0.0636

         h = 13,205.4 m

b) For this part we are asked to use the law of universal gravitation, write the energy

starting point. Satellite surface

           Em₀ = K + U = ½ m v² - GmM / r_o

final point. Where the ball stops

            Em_{f}= U = - G mM / r_f

          Em₀ = Em_{f}

          ½ m v² - G m M / r_o = - G mM / r_f

In this case all distances are measured from the center of the satellite

         1 / rf = 1 / GM (-½ v² + G M / r_o)

     

let's calculate

         1 / rf = 1 / (6.67 10⁻¹¹ 3.75 10¹⁹) (- ½ 41 2 + 6.67 10⁻¹¹ 3.75 10¹⁹ / 1.98 105)

         1 / r_f = 3,998 10⁻¹¹(-840.5 + 12.63 10³)

          1 / r_f = 4,714 10⁻⁷

          r_f = 1 / 4,715 10⁻⁷

          r_f = 2.12 106 m

to measure this distance from the satellite surface

          r_f ’= r_f - r_o

          r_f ’= 2.12 106 - 1.98 105

         r_f ’= 1,922 106 m

c) the percentage difference is

          e% = 13 205.4 / 1,922 106 100

          e% = 0.68%

The estimate of part a is a little low

6 0
3 years ago
Part III: If a mouse and an elephant both run with the same kinetic energy, can you say which is running faster? Use the space b
Verdich [7]

Answer:

The mouse runs faster to have the same kinetic energy as the elephant.

Explanation:

Note from the equation given, mass (m) is directly proportional to KE. This means an elephant with more mass will have more KE, therefore, for the mouse to compensate, it has to run faster because its KE is smaller because of its small mass. If both run at the same speed, the elephant would have thousands of times more kinetic energy than the mouse. So the mouse has to run faster so that its speed compansates for its smaller weight.

3 0
3 years ago
What type of properties would a scientist need to know to correctly place in new element into a group?
V125BC [204]
Placing elements into columns, groups, rows and periods that share certain properties. properties such as gas, solid and liquid determine an element physical state at room temperature. 
3 0
3 years ago
What pressing problem did the invention of the cotton gin solve?
AlexFokin [52]
Are you answering a question or asking? You have already seemed to get the answer, A is the correct answer :I
4 0
3 years ago
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