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3 years ago

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An isotope is a version of the same element that differs in the composition of the A) atom. B) nucleus. C) particle. Eliminate D

) electron cloud.

2 answers:

crimeas [40]3 years ago

5 0

The correct answer is B because isotopes have different numbers of neutrons, and neutrons are located in the nucleus

Hope this helps

worty [1.4K]3 years ago

5 0

The answers B. Hopes this helps

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The transfer of energy by electromagnetic

chubhunter [2.5K]

Either convection or thermal energy

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3 years ago

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According to principle of conservation of energy, the total momentum of a system of masses in any direction remains constant unl

Sergeu [11.5K]

The principle of conservation of energy states that energy can neither be created nor destroyed, but can be changed from one form to another. The law of inertia on the other hand states that a body remains at a state of rest or motion on a straight line unless compelled by an external force. So i think that the answer is B, which is FALSE because the question is more related to the law of inertia(Newtons first law) than to the law of conservation of energy. Hope i helped.

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3 years ago

The Atomic Mass of an element is

dedylja [7]

Answer:

C) A ratio based on the mass of a carbon-12 atom

Explanation:

For each element, there is a characteristic number of protons, this number represent a type of atom and its called the atomic number

On the other hand we have the number of neutrons, and for one element which difers only on the number of neutrons, we have different isotopes from one element.

Together, protons and neutrons define the mass number

One property linked with the mass number, is the atomic mass, which is formerly expressed as "uma" (atomic mass unit)

By definition, one atom of carbon-12 (with 6 neutrons) has an atomic mass of 12 umas

6 0

4 years ago

Read 2 more answers

A large capacitor in an air conditioner is typically connected to the potential difference provided to your house (120 V). Altho

fomenos

Answer:

$A=7.72\times 10^{-18}\ m^2$

Explanation:

Given:

the voltage of the source, $V=120\ V$

distance of separation between the capacitor plates, $d=2\times 10^{-3}\ J$

energy of the capacitor, $U=0.25\ J$

Assuming that there is free space between the plates, so the permittivity, $\epsilon=9\times 10^{9}\ N.m^2.C^{-2}$

<u>We have the energy stored in a capacitor as:</u>

$U=\frac{1}{2}\times \frac{\epsilon.A.V^2}{d}$

$0.25=0.5\times \frac{9\times 10^{9}\times A\times 120^2}{2\times 10^{-3}}$

$A=7.72\times 10^{-18}\ m^2$

5 0

4 years ago

Read 2 more answers

A potter's wheel is spinning with an initial angular velocity of 11 rad/s . It rotates through an angle of 80.0 rad in the proce

Grace [21]

The angular acceleration of the wheel approximately <u>-0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s</u>.
It need approximately <u>14.474 s</u> to come to rest.

<h2>Introduction</h2>

Hi ! I will help you to discuss about Proportionally Changes in Circular Motion. The analogy of proportionally changes in circular motion is same as the analogy of proportionally changes in direct motion. Here you will hear again the terms acceleration and change in speed, only expressed in the form of a certain angle coverage. Before that, in circular motion, it is necessary to know the following conditions:

1 rotation = 2π rad
1 rps = 2π rad/s
1 rpm = $\sf{\frac{1}{60} \: rps}$ = $\sf{\frac{1}{30}\pi \: rad/s}$

<h2>Formula Used</h2>

The following equations apply to proportionally changes circular motion:

<h3>Relationship between Angular Acceleration and Change of Angular Velocity </h3>

$\boxed{\sf{\bold{\omega_t = \omega_0 + \alpha \times t}}}$

With the following conditions:

$\sf{\omega_t}$ = final angular velocity (rad/s)
$\sf{\omega_0}$ = initial angular velocity (rad/s)
$\sf{\alpha}$ = angular acceleration (rad/s²)
t = interval of the time (s)

<h3>Relationship between Angular Acceleration and Change of $\sf{\theta}$ (Angle of Rotation) </h3>

$\boxed{\sf{\bold{\theta = \omega_0 \times t + \frac{1}{2} \times \alpha \times t^2}}}$

Or

$\boxed{\sf{\bold{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}}}$

With the following condition :

$\sf{\theta}$ = change of the sudut (rad)
$\sf{\alpha}$ = angular acceleration (rad/s²)
t = interval of the time (s)
$\sf{\omega_t}$ = final angular velocity (rad/s)
$\sf{\omega_0}$ = initial angular velocity (rad/s)

<h2>Problem Solving</h2>

We know that :

$\sf{\omega_t}$ = final angular velocity = 0 rad/s >> see in the sentence "in the process of coming to rest."
$\sf{\omega_0}$ = initial angular velocity = 11 rad/s
$\sf{\theta}$ = change of the sudut = 80.0 rad

What was asked :

$\sf{\alpha}$ = angular acceleration = ... rad/s²
t = interval of the time = ... s

Step by step :

$\sf{\alpha}$ = ... rad/s²

$\sf{(\omega_t)^2= (\omega_0)^2 + 2 \times \alpha \times \theta}$

$\sf{0^2= (11)^2 + 2 \times \alpha \times 80}$

$\sf{0 = 121 + 160 \alpha}$

$\sf{-160 \alpha = 121}$

$\sf{\alpha = \frac{121}{-160}}$

$\sf{\alpha = -0.75625 \: rad/s^2 \approx \boxed{-0.76 \: rad/s^2}}$

t = ... s

$\sf{\alpha = \frac{\omega_0 - \omega_t}{t}}$

$\sf{-0.76 = \frac{0 - 11}{t}}$

$\sf{-0.76t = -11}$

$\sf{t = \frac{- 11}{-0.76}}$

$\boxed{\sf{t \approx 14.474 \: s}}$

<h3>Conclusion</h3>

So :

The angular acceleration of the wheel approximately -0.76 rad/s² or proportionally as deceleration approximately 0.76 rad/s.
It need approximately 14.474 s to come to rest.

5 0

2 years ago