SO₄²⁻ +NH₃ → SO₃²⁻ + H₂O +N₂
The balanced of the above redox reaction is as below
3SO₄²⁻ + 2NH₃ → 3SO₃²⁻ + 3 H₂O + N₂
Explanation
According to the law of mass conservation the number of atoms in the reactant side must be equal to number of atoms in product side.
Inserting coefficient 3 in front of SO₄² , 2 in front of NH₃, 3 in front of SO₃²⁻ and 3 in front of H₂O balance the equation above. This is because the number of atoms are equal in both side.
for example there are 2 atoms of N in both side of the reaction.
The answer is 3. As 5 * 3 = 15.
Is there any other equations I may be able to help you with? :)
<span>H2SO4 gives 2 moles oh H+ per mole of acid
[H2SO4] = 2M so [H+] = 4M
pH = -log(4) = -.6
Therefore, the pH </span><span>of a 2.0 M H2SO4 solution is -0.6
</span>
I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!
Answer:
1.146 x 10⁴ year.
Explanation:
- The decay of carbon-14 is a first order reaction.
- The rate constant of the reaction (k) in a first order reaction = ln (2)/half-life = 0.693/(5730 year) = 1.21 x 10⁻⁴ year⁻¹.
- The integration law of a first order reaction is:
<em>kt = ln [A₀]/[A]</em>
<em></em>
k is the rate constant = 1.21 x 10⁻⁴ year⁻¹.
t is the time = ??? years.
[A₀] is the initial percentage of carbon-14 = 100.0 %.
[A] is the remaining percentage of carbon-14 = 1/4[A₀] = 25.0 %.
∵ kt = ln [Ao]/[A]
∴ (1.21 x 10⁻⁴ year⁻¹)(t) = ln (100.0%)/[25.0 %]
(1.21 x 10⁻⁴ year⁻¹)(t) = 1.386.
∴ <em>t </em>= 1.386/
(1.21 x 10⁻⁴ year⁻¹) = <em>1.146 x 10⁴ year.</em>
