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AlladinOne [14]
3 years ago
5

A drop of water placed on a smooth, dry surface will form a dome-shaped droplet instead of flowing outward in different directio

ns. Which of these best explains this observation?
A. The bonds between hydrogen and oxygen atoms are too strong.
B. The electrons in the atom attract the electrons in other atoms.
C. Water molecules at the surface experience fewer hydrogen bonds than water molecules within the liquid
D. Water molecules near the surface produce more buoyant force than water molecules within the liquid.
Chemistry
2 answers:
Dafna1 [17]3 years ago
7 0
Your answer is C Water molecules at the surface experience fewer hydrogen bonds than water molecules within the liquid.
KIM [24]3 years ago
4 0
<h2>Answer:</h2>

The correct answer is option C which is,<u> "Water molecules at the surface experience fewer hydrogen bonds than water molecules within the liquid".</u>

<h3>Explanation:</h3>
  • In some conditions, a water droplet remains in the droplet form on the dry surface rather than spreading on the whole surface. It covers only remains on the mall part of the surface and making a dome shape.
  • It is due to the fact that the hydrogen bond between the water molecules is much strong than the attraction between the water molecules and surface.
  • Hence the option C is correct.

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Identify the Lewis acid and Lewis base from among the reactants in each of the following equations.
Alex

Answer:

Part A

Ag+ is the Lewis acid and NH3 is the Lewis base.

Part B

AlBr3 is the Lewis acid and NH3 is the Lewis base.

Part C

AlCl3 is the Lewis acid and Cl− is the Lewis base.

Explanation:

A Lewis acid is any specie that accepts a lone pair of electrons. Ag^+, AlBr3 and AlCl3 all accepted lone pairs of electrons according to the three chemical reaction equations shown. Hence, they are Lewis acids.

A Lewis base donates a lone pair of electrons. They include neutral molecules having lone pair of electrons such as NH3 or negative ions such as Cl- .

3 0
3 years ago
An aqueous solution containing 17.5 g of an unknown molecular (nonelectrolyte) compound in 100.0 g of water has a freezing point
Sonbull [250]

Answer:

molar mass = 180.833 g/mol

Explanation:

  • mass sln = mass solute + mass solvent

∴  solute: unknown molecular (nonelectrolyte)

∴ solvent: water

∴ mass solute = 17.5 g

∴ mass solvent =  100.0 g = 0.1 Kg

⇒ mass sln = 117.5 g

freezing point:

  • ΔTc = - Kc×m

∴ ΔTc = -1.8 °C

∴ Kc H2O = 1.86 °C.Kg/mol

∴ m: molality (mol solute/Kg solvent)

⇒ m = ( - 1.8 °C)/( - 1.86 °C.Kg/mol)

⇒ m = 0.9677 mol solute/Kg solvent

  • molar mass (Mw) [=] g/mol

∴ mol solute = ( m )×(Kg solvent)

⇒ mol solute = ( 0.9677 mol/Kg) × ( 0.100 Kg H2O )

⇒ mol solute = 0.09677 mol

⇒ Mw solute = ( 17.5 g ) / ( 0.09677 mol )

⇒ Mw solute = 180.833 g/mol

6 0
3 years ago
How many atoms of both elements are there in this molecule: 3N205; O 3 Nitrogen and 15 Oxygen 6 Nitrogen and 5 Oxygen KD 2 Nitro
abruzzese [7]

Answer:

Explanation:

oxygen is a 15 and nitrogen science chemistry i'm guessing

6 0
3 years ago
n a semiconductor, the bonding molecular orbitals that contain electrons are referred to as the ________, while the antibonding
Kruka [31]

Answer:

In a semiconductor, the bonding molecular orbitals that contain electrons are referred to as the valence band, while the antibonding orbitals that are completely empty are referred to as the conduction band.

The conduction band occupies a higher energy level than the valence band. The band gap is what separates the two orbitals.

3 0
2 years ago
A solution of HNO3HNO3 is standardized by reaction with pure sodium carbonate. 2H++Na2CO3⟶2Na++H2O+CO2 2H++Na2CO3⟶2Na++H2O+CO2 A
Gemiola [76]

Answer:

(0,653±0,002) M of HNO₃

Explanation:

The reaction of standarization of HNO₃ with Na₂CO₃ is:

2 HNO₃ + Na₂CO₃ ⇒ 2 Na⁺ + H₂O + CO₂ + 2NO₃⁻

To obtain molarity of HNO₃ we need to know both moles and volume of this acid. The volume is (27,71±0,05) mL and to calculate the moles it is necessary to obtain the Na₂CO₃ moles and then convert these to HNO₃ moles, thus:

0,9585 g of Na₂CO₃ × ( 1 mole / 105,988 g) =

9,043×10⁻³ mol Na₂CO₃ × ( 2 moles of HNO₃ / 1 mole of Na₂CO₃) = 1,809×10⁻² moles of HNO₃

Molarity is moles divide liters, thus, molarity of HNO₃ is:

1,809×10⁻² moles / 0,02771 L = 0,6527 M of HNO₃

The absolute uncertainty of multiplication is the sum of relative uncertainty, thus:

ΔM = 0,6527M× (0,0007/0,9585 + 0,001/105,988 + 0,05/27,71) =

0,6527 M× 2,54×10⁻³ = 1,7×10⁻³ M

Thus, molarity of HNO₃ solution and its absolute uncertainty is:

(0,653±0,002) M of HNO₃

I hope it helps!

5 0
3 years ago
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