Answer:
It would take 3.11 J to warm 3.11 grams of gold
Explanation:
Step 1: Data given
Mass of gold = 3.11 grams
Temperature rise = 7.7 °C
Specific heat capacity of gold = 0.130 J/g°C
Step 2: Calculate the amount of energy
Q = m*c*ΔT
⇒ Q = the energy required (in Joules) = TO BE DETERMINED
⇒ m = the mass of gold = 3.11 grams
⇒ c = the specific heat of gold = 0.130 J/g°C
⇒ ΔT = The temperature rise = 7.7 °C
Q = 3.11 g * 0.130 J/g°C * 7.7 °C
Q = 3.11 J
It would take 3.11 J to warm 3.11 grams of gold
Answer:
The answer is
<h2>4.69 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of wood = 4.6 g
density = 0.98 g/mL
It's volume is

We have the final answer as
<h3>4.69 mL</h3>
Hope this helps you
Boiling point is the temperature at which the substance boils. Boiling point for water is 212F