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3 years ago

Describe the protons, electrons, and neutrons of an atom of hydrogen-2.

Chemistry

2 answers:

AlladinOne [14]3 years ago

6 0

Answer:

However, various hydrogen isotopes, such as H-2, have one proton and one neutron; H-3 has one proton and two neutrons, etc. The sum of the protons and neutrons in an atom's nucleus is its atomic mass. Thus, the atomic mass of the H-2 isotope is two, the atomic mass of the H-3 isotope is three, and so forth.

Explanation:

Leno4ka [110]3 years ago

4 0

Answer:

1 proton, 1 neutron and 1 electron.

Explanation:

This isotope of hydrogen, also called deuterium, has 1 neutron in the nucleus. Deuterium oxide is present in heavy water.

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An order is given to administer methylprednisolone, an anti-inflammatory drug, by IV at a rate of 39 mg every 30 min. The IV bag

Korvikt [17]

Answer:

The Flow rate = 0.0208 mL/min

Explanation:

Data provided:

Rate of dose = 39 mg every 30 min = (39/30) mg/min = 1.3 mg/min

also,

125mg of methylprednisolone is present in every 2 mL

thus,

concentration = (125/2) mg/mL = 62.5 mg/mL

Now,

The flow rate is given as:

Flow rate = Rate / Concentration

on substituting the respective values, we get

Flow rate = (1.3 mg/min) / (62.5mg/mL)

The Flow rate = 0.0208 mL/min

3 0

3 years ago

Drawing a conclusion derived from knowledge of an established principle is called _____. inductive reasoning abductive reasoning

san4es73 [151]

a.)Inductive Reasoning

is the answer

5 0

3 years ago

Read 2 more answers

48.0 mL of 1.70 M CuCl2(aq) and 57.0 mL of 0.800 M (NH4)2S(aq) are mixed together to give CuS(s) as a precipitate. The other pro

artcher [175]

Answer:

The concentration of the Cu(II) ion is 0.777M

Explanation:

Step 1: Data given

Volume of 1.70 M CuCl2 = 48.0 mL = 0.0480 L

Volume of 0.800 M (NH4)2S = 57.0 mL = 0.0570 L

Step 2: The balanced equation

CuCl2 (aq) + (NH4)2S (aq) → 2 NH4Cl (aq) + CuS (s)

Step 3: Calculate moles CuCl2

moles CuCl2 = 0.0480 L * 1.70 M=0.0816 moles

Step 4: Calculate moles (NH4)2S

moles (NH4)2S = 0.0570 L * 0.800 M = 0.0456 moles

Step 5: Calculate the limiting reactant

The ratio between CuCl2 and (NH4)2S is 1 : 1 so (NH4)2S is the limiting reactant . IT will completely be consumed (0.0456 moles).

CuCl2 is in excess. There will remain 0.0816 - 0.0456 = 0.0360 moles

Step 6: Calculate moles of CuS

For 1 mol CuCl2 we need 1 mol (NH4)2S to produce 2 moles of NH4Cl and 1 mol CuS

For 0.0456 moles we'll produce 0.0456 moles CuS

Step 7: Calculate moles of Cu(II)ion

There remains 0.0360 moles CuCl2.

There will be 0.0456 moles CuS produced

Total moles Cu^2+ = 0.0816 moles

Step 8: Calculate concentration of Cu(II) ion

Concentration = moles / volume

Concentration = 0.0816 moles / (0.048+0.057)

Concentration = 0.777 M

The concentration of the Cu(II) ion is 0.777M

7 0

3 years ago

The humidity levels inside the greenhouse.

PtichkaEL [24]

Answer:

Most indoor growers will want to aim for 50-70% relative humidity, although 60-80% is usually tolerable.

Explanation:

7 0

3 years ago

In an experiment, 8.50 g of methane, CH4, was reacted with 15.9 g of oxygen gas to produce carbon dioxide and water. Determine t

exis [7]

Answer:

89.3 %

Explanation:

M(CH4) = 12+ 4*1 = 16 g/mol

M(O2) = 2*16 = 32 g/mol

M(CO2) = 12 + 2*16 = 44 g/mol

8.50 g * 1 mol/16 g = 0.5313 mol CH4

15.9 g * 1 mol/32 g = 0.4969 mol O2

9.77 g * 1 mol/44 g = 0.2220 mol CO2

1) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 1 mol 2 mol

given 0.5313 mol (0.4969 mol)

1 mol CH4 --- 2 mol O2

0.5313 mol CH4 --- x mol O2

x= 2*0.5313 = 1.0626 mol O2

We can see that for given amount of CH4 we do not have enough O2, so O2 is a limiting reactant.

2) CH4 + 2O2 -----> CO2 + 2H2O

from reaction 2 mol 1 mol

given 0.4969 mol x mol

x = 0.4969*1/2 = 0.2485 mol CO2 theoretical yield

Practical yield CO2 = 0.2220 mol

Theoretical yield CO2 = 0.2485 mol

% yield = (0.2220/0.2485)*100% = 89.3 %

7 0

3 years ago