Answer:
D. The rate decreases as reactants are used up.
Explanation:
Initially, the rate increases until the reaction is at equilibrium. At equilibrium, the rate is constant.
As the reaction progresses, the rate decreases to zero when reactants are used up ( for irriversible reactions only )
<u>Answer:</u> The concentration of the solution is 0.25 M
<u>Explanation:</u>
Let the volume of solution of 2.5 M NaCl be 10 mL
We are given:
Dilution ratio = 1 : 10
So, the solution prepared will have a volume of = ![\frac{10}{1}\times 1000=100mL](https://tex.z-dn.net/?f=%5Cfrac%7B10%7D%7B1%7D%5Ctimes%201000%3D100mL)
To calculate the molarity of the diluted solution, we use the equation:
where,
are the molarity and volume of the concentrated NaCl solution
are the molarity and volume of diluted NaCl solution
We are given:
Putting values in above equation, we get:
![2.5\times 10=M_2\times 100\\\\M_2=\frac{2.5\times 10}{100}=0.25M](https://tex.z-dn.net/?f=2.5%5Ctimes%2010%3DM_2%5Ctimes%20100%5C%5C%5C%5CM_2%3D%5Cfrac%7B2.5%5Ctimes%2010%7D%7B100%7D%3D0.25M)
Hence, the concentration of the solution is 0.25 M
The number of moles contained in 39 L of F2 gas at STP is 1.74mol. Details on how to calculate number of moles can be found below.
<h3>How to calculate number of moles?</h3>
The number of moles of a gas at STP can be calculated using the following formula:
PV = nRT
Where;
- P = pressure
- V = volume
- n = number of moles
- R = gas law constant
- T = temperature
At STP, the following applies:
- T = 273K
- P = 1 atm
- R = 0.0821 Latm/molK
1 × 39 = n × 0.0821 × 273
39 = 22.41n
n = 1.74mol
Therefore, the number of moles contained in 39 L of F2 gas at STP is 1.74mol.
Learn more about number of moles at: brainly.com/question/14919968
False, because generally forensics collect the evidence to make sure the evidence doesn’t get damaged or tainted.... hope this helps
Answer:
A linear molecule has a bond angle of 180°