Answer:
Determine the pH of the solution half-way to the end-point on the pH titration curve for acetic acid.
Explanation:
The equation for the ionization of acetic acid is
HA + H₂O ⇌ H₃O⁺ + A⁻
For points between the starting and equivalence points, the pH is given by the Henderson-Hasselbalch equation:
![\text{pH} = \text{pK}_{\text{a}} + \log\dfrac{[\text{A}^{-}]}{\text{[HA]}}](https://tex.z-dn.net/?f=%5Ctext%7BpH%7D%20%3D%20%5Ctext%7BpK%7D_%7B%5Ctext%7Ba%7D%7D%20%2B%20%5Clog%5Cdfrac%7B%5B%5Ctext%7BA%7D%5E%7B-%7D%5D%7D%7B%5Ctext%7B%5BHA%5D%7D%7D)
At the half-way point, half of the HA has been converted to A⁻, so [HA] = [A⁻]. Then,
The pKₐ is the pH at the half-way point in the titration.
Well, if you are moving forward in a direction, then your velocity is your speed with the direction you are moving in. To calculate velocity, you divide your distance traveled by the time it took to travel that distance and you add your direction to it.
So to conclude, 300/100= 3 m/s South
Answer:
the answer is 0.4588162459
Explanation:
1 mole = 0.010195916576195
= 45 ×"
To solve this, we need the Avogadros number to convert to
moles then multiply with molar mass to convert to mass in grams.
moles = 9.3 x 10^23 molecules * (1 mol / 6.022 x 10^23
molecules)
moles = 1.54 moles
Molar mass of NH3 is 17 g/mol:
mass = 1.54 moles * 17 g/mol
<span>mass = 26.25 g</span>
15c - 1.2m
1c - 1.2/15 = 0.08m
65c - 5.2m
